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3 years ago

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The length of a train is about 1,700 meters. If there are approximately 3.28 feet in one meter, what is the length of the train

in feet?
0.002 feet

557,600 feet

5,576 feet

518 feet

1 answer:

melisa1 [442]3 years ago

5 0

It should be 5,576 feet

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How many Erving of 3/4 cup of beans are in half a cup?

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Well a half cup is 2/4 and if the serving size is 3/4 there is only 66.66% of the serving size needed hope this helps!

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What digit is in the tenths place in this number?<br><br> 748.59

Kamila [148]

5 would be the digit in the tenths place

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3 years ago

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Solve for x.<br> 5<br> 10<br> 12<br> 13

zysi [14]

Answer: B) 4 & 1/6

Nice work on getting the correct answer.

============================================================

Explanation:

x is opposite the marked acute angle

5 is opposite the corresponding acute angle

So x and 5 are proportional to each other. We can form the ratio x/5

Similarly, 10 and 12 are proportional to one another. We can form the ratio 10/12.

Set those ratios equal to each other and solve for x

x/5 = 10/12

12x = 5*10 ... cross multiply

12x = 50

x = 50/12 ...... divide both sides by 12

x = (25*2)/(6*2)

x = 25/6

x = (24+1)/6

x = 24/6 + 1/6

x = 4 + 1/6

x = 4 & 1/6 which shows why <u>choice B</u> is the answer.

Side note: 25/6 = 4.167 approximately

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41% of U.S. adults have very little confidence in newspapers. You randomly select 10 U.S. adults. Find the probability that the

lys-0071 [83]

Answer:

a) 0.2087 = 20.82% probability that the number of U.S. adults who have very little confidence in newspapers is exactly five.

b) 0.1834 = 18.34% probability that the number of U.S. adults who have very little confidence in newspapers is at least six.

c) 0.3575 = 35.75% probability that the number of U.S. adults who have very little confidence in newspapers is less than four.

Step-by-step explanation:

For each adult, there are only two possible outcomes. Either they have very little confidence in newspapers, or they do not. The answers of each adult are independent, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

41% of U.S. adults have very little confidence in newspapers.

This means that $p = 0.41$

You randomly select 10 U.S. adults.

This means that $n = 10$

(a) exactly five

This is $P(X = 5)$ . So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 5) = C_{10,5}.(0.41)^{5}.(0.59)^{5} = 0.2087$

0.2087 = 20.82% probability that the number of U.S. adults who have very little confidence in newspapers is exactly five.

(b) at least six

This is:

$P(X \geq 6) = P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 6) = C_{10,6}.(0.41)^{6}.(0.59)^{4} = 0.1209$

$P(X = 7) = C_{10,7}.(0.41)^{7}.(0.59)^{3} = 0.0480$

$P(X = 8) = C_{10,8}.(0.41)^{8}.(0.59)^{2} = 0.0125$

$P(X = 9) = C_{10,9}.(0.41)^{9}.(0.59)^{1} = 0.0019$

$P(X = 10) = C_{10,10}.(0.41)^{10}.(0.59)^{0} = 0.0001$

Then

$P(X \geq 6) = P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10) = 0.1209 + 0.0480 + 0.0125 + 0.0019 + 0.0001 = 0.1834$

0.1834 = 18.34% probability that the number of U.S. adults who have very little confidence in newspapers is at least six.

(c) less than four.

This is:

$P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{10,0}.(0.41)^{0}.(0.59)^{10} = 0.0051$

$P(X = 1) = C_{10,1}.(0.41)^{1}.(0.59)^{9} = 0.0355$

$P(X = 2) = C_{10,2}.(0.41)^{2}.(0.59)^{8} = 0.1111$

$P(X = 3) = C_{10,3}.(0.41)^{3}.(0.59)^{7} = 0.2058$

So

$P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0051 + 0.0355 + 0.1111 + 0.2058 = 0.3575$

0.3575 = 35.75% probability that the number of U.S. adults who have very little confidence in newspapers is less than four.

5 0

3 years ago

A-(5,-9)<br> B-(-9,-5)<br> C-(-9,5)<br> D-(-5,9)<br><br> ASAP HELP!!! WILL MARK BRAINLIST!!!

slava [35]

It’s supposed to be (5,9) both numbers positive

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3 years ago