Answer:
a) 11%
b) 56%
Step-by-step explanation:
a) A= πr^2 6^2π= 36π A= 18^2π = 324π
36π/324π = .111111111111111111111111 or 11%
remember to cancel out the pi symbols when you are showing your work
(put a line across the pi symbols when dividing)
b) A= πr^2 18^2 π = 324π
A= πr^2 12^2π = 144π
324 – 144 = 180
180π/324π = .5555555555555555555555556 or 56%
remember to cancel out the pi symbols when you are showing your work
(put a line across the pi symbols when dividing)
14c³d²-21c²d³/14cd
= (196c^4d³-21c²d³)/ 14cd
= (196c³d²-21cd²)/14
= (28c³d²-3cd²)/2
I hope that's help !
Answer:
59 ° F
Step-by-step explanation:
F = 9/5 C + 32
= 9/5 (15) + 32 = 59 ° F
Should would have $1,642.86 in her account
Answer:
The parenthesis need to be kept intact while applying the DeMorgan's theorem on the original equation to find the compliment because otherwise it will introduce an error in the answer.
Step-by-step explanation:
According to DeMorgan's Theorem:
(W.X + Y.Z)'
(W.X)' . (Y.Z)'
(W'+X') . (Y' + Z')
Note that it is important to keep the parenthesis intact while applying the DeMorgan's theorem.
For the original function:
(W . X + Y . Z)'
= (1 . 1 + 1 . 0)
= (1 + 0) = 1
For the compliment:
(W' + X') . (Y' + Z')
=(1' + 1') . (1' + 0')
=(0 + 0) . (0 + 1)
=0 . 1 = 0
Both functions are not 1 for the same input if we solve while keeping the parenthesis intact because that allows us to solve the operation inside the parenthesis first and then move on to the operator outside it.
Without the parenthesis the compliment equation looks like this:
W' + X' . Y' + Z'
1' + 1' . 1' + 0'
0 + 0 . 0 + 1
Here, the 'AND' operation will be considered first before the 'OR', resulting in 1 as the final answer.
Therefore, it is important to keep the parenthesis intact while applying DeMorgan's Theorem on the original equation or else it would produce an erroneous result.
