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3 years ago

11

a cube of wood exerts a pressure of a 2pa when it is placed on a floor . What is the force exerted by the cube of its surface ar

ea is 5m square?

1 answer:

sertanlavr [38]3 years ago

6 0

Answer:

the force exerted is 10 newton

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Convert 15 km per hour to meters per second

ipn [44]

1km = 1000m
1hr = 3600sec

Do proportions:
1km / 1000m = 15km / x
15000m = x

1hr = 3600sec

15000/3600 = 4.2m per second
Choice 4

6 0

2 years ago

15 points for someone who can answer & explain this to me thanks

iris [78.8K]

Answer:

see explanation

Step-by-step explanation:

Given

$\frac{9}{a^2+9a+20}$ , $\frac{7a}{a^2+11a+28}$

Factor the denominators of both fractions

$\frac{9}{(a+4)(a+5)}$ , $\frac{7a}{(a+4)(a+7)}$

The lowest common denominator of both fractions is (a + 4)(a + 5)(a + 7)

Multiply numerator/denominator of first fraction by (a + 7)

Multiply numerator/denominator of second fraction by (a + 5 )

$\frac{9(a+7)}{(a+4)(a+5)(a+7)}$ , $\frac{7a(a+5)}{(a+4)(a+5)(a+7)}$ , then

$\frac{9a+63}{(a+4)(a+5)(a+7)}$ , $\frac{7a^2+35a}{(a+4)(a+5)(a+7)}$

8 0

2 years ago

What is the slope-intercept form of the line passing through the point (2, 1) and having a slope of 4?

patriot [66]

Answer:

1=4(2)-7

Step-by-step explanation:

y=mx+b

b=where it crosses the y-axis

m=slope

1=4(2)-7

6 0

3 years ago

An apartment complex rents an average of 2.3 new units per week. If the number of apartment rented each week Poisson distributed

masya89 [10]

Answer:

$P(X\leq 1) = 0.331$

Step-by-step explanation:

Given

Poisson Distribution;

Average rent in a week = 2.3

Required

Determine the probability of renting no more than 1 apartment

A Poisson distribution is given as;

$P(X = x) = \frac{y^xe^{-y}}{x!}$

Where y represents λ (average)

y = 2.3

<em>Probability of renting no more than 1 apartment = Probability of renting no apartment + Probability of renting 1 apartment</em>

<em />

Using probability notations;

$P(X\leq 1) = P(X=0) + P(X =1)$

Solving for P(X = 0) [substitute 0 for x and 2.3 for y]

$P(X = 0) = \frac{2.3^0 * e^{-2.3}}{0!}$

$P(X = 0) = \frac{1 * e^{-2.3}}{1}$

$P(X = 0) = e^{-2.3}$

$P(X = 0) = 0.10025884372$

Solving for P(X = 1) [substitute 1 for x and 2.3 for y]

$P(X = 1) = \frac{2.3^1 * e^{-2.3}}{1!}$

$P(X = 1) = \frac{2.3 * e^{-2.3}}{1}$

$P(X = 1) =2.3 * e^{-2.3}$

$P(X = 1) = 2.3 * 0.10025884372$

$P(X = 1) = 0.23059534055$

$P(X\leq 1) = P(X=0) + P(X =1)$

$P(X\leq 1) = 0.10025884372 + 0.23059534055$

$P(X\leq 1) = 0.33085418427$

$P(X\leq 1) = 0.331$

Hence, the required probability is 0.331

6 0

2 years ago

I just like to get to the dance for 3.95 each, the student council brought in 1020.50 for ticket sales. How many tickets the stu

MakcuM [25]

1020.50 divided by 3.95 would equal 258

6 0

3 years ago