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3 years ago

Please help me and explain

Mathematics

2 answers:

MatroZZZ [7]3 years ago

6 0

Answer:

the answers would be 12/35

because you all the animals together including the wolf and bobcat which is 35. so then you add the wolf and bobcat separately which is 12

lapo4ka [179]3 years ago

6 0

Answer:

<h2>answer will be </h2><h2>12/35</h2>

Step-by-step explanation:

<h2>total no. of animal= 16+7+5+7=35</h2><h2>and</h2><h2>total bobcat and wolf =5+7=12</h2><h2>so. </h2><h2>probability=12/35</h2><h2>--------------------------</h2><h2>plzzzz mark it as a brilliant ans</h2>

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Answer:

$\huge\boxed{\sqrt{25^{3}}}$

Step-by-step explanation:

When we have a number to a fraction power, we need to note that

It's the same as taking the denominator root of the base to the numerator power

Basically, for example, $5^{\frac{1}{2}}$ is the same as $\sqrt{5}$ since the numerator is 1 ( $5^1 = 5$ ) and the denominator is 2 ( $\sqrt{5}$ ).

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3 years ago

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$28.50

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3 years ago

A=2 b=3 c=4 1) ab - c = 2) 6c - 2b= 3) a + b - c + 5 = 4) 7c - 2a =

bekas [8.4K]

Step-by-step explanation:

1)ab-c

=2(3)-4

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4 years ago

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Dafna11 [192]

Answer:

Radius=2.09 cm

Height,h=14.57 cm

Step-by-step explanation:

We are given that

Volume of cylinderical shaped can=200 cubic cm.

Cost of sides of can=0.02 cents per square cm

Cost of top and bottom of the can =0.07 cents per square cm

Curved surface area of cylinder= $2\pi rh$

Area of circular base=Area of circular top= $\pi r^2$

Total cost,C(r)= $0.02\times 2\pi rh+2\pi r^2\times 0.07$

Volume of cylinder, $V=\pi r^2 h$

$200=\pi r^2 h$

$h=\frac{200}{\pi r^2}$

Substitute the value of h

$C(r)=0.02\times 2\pi r\times \frac{200}{\pi r^2}+2\pi r^2\times 0.07$

$C(r)=\frac{8}{r}+0.14\pi r^2$

Differentiate w.r.t r

$C'(r)=-\frac{8}{r^2}+0.28\pi r$

$C'(r)=0$

$-\frac{8}{r^2}+0.28\pi r=0$

$0.28\pi r=\frac{8}{r^2}$

$r^3=\frac{8}{0.28\pi}=9.095$

$r=(9.095)^{\frac{1}{3}}=2.09$

Again, differentiate w.r.t r

$C''(r)=\frac{16}{r^3}+0.28\pi$

Substitute the value of r

$C''(2.09)=\frac{16}{(2.09)^3}+0.28\pi=2.63>0$

Therefore,the product cost is minimum at r=2.09

h= $\frac{200}{\pi (2.09)^2}=14.57$

Radius of can,r=2.09 cm

Height of cone,h=14.57 cm

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Answer:

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Step-by-step explanation:

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