<span>y(t) = a exp(3t) + b exp(4t)
conditions, y(0) = 3
y'(0) = 3
y(0) = a exp(3 x 0) + b exp(4 x 0)
= a exp(0) + b exp(0)
= (a x 1) + (b x 1)
= a + b
y'(0) = 0
so the linear equation is, a + b = 3</span>
Answer:If two lines are cut by a transversal and the consecutive interior angles are supplementary ...
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Answer:
I think 60 - 1200 but i am not conform
Answer:
B
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