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3 years ago

Which system of equations below has no solution

Mathematics

2 answers:

Luda [366]3 years ago

7 0

Answer:

Step-by-step explanation:

y= 4x + 5

y = 4x - 5

4x + 5 = 4x - 5

0 ≠ -10

no solution

storchak [24]3 years ago

3 0

Answer:

\A. 4x+5=4x-5

4x+10=4x

10=0

B. 4x+5=4x+5

C.4x+5=1/4+5

4x=1/4

16x=1

x=16

D. 4x+5=8x+10

-4x=5

x=-5/4

A. has no solution

Step-by-step explanation:

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3 years ago

Quesheip Use the number line below, where RS = 6y +2, ST=5y + 9, and RT= 13y - 1 a What is the value of y? b Find RS, ST, and RT

Simora [160]

Answer:

$y = 6$

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$ST = 39$

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Step-by-step explanation:

Given:

$RS = 6y +2$

$ST=5y + 9$

$RT= 13y - 1$

Solving (a): The value of y

From the given parameters, we understand that

$RT = RS + ST$

Substitute values for RS, ST and RT

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Collect Like Terms

$13y - 6y - 5y = 1 + 2 + 9$

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Divide both sides by 2

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Solving (b):

The value of RS

Substitute 6 for y in $RS = 6y +2$

$RS = 6 * 6 + 2$

$RS = 36 + 2$

$RS = 38$

The value of ST

Substitute 6 for y in $ST=5y + 9$

$ST = 5 * 6 + 9$

$ST = 30 + 9$

$ST = 39$

The value of ST

Substitute 6 for y in $RT= 13y - 1$

$RT = 13 * 6 - 1$

$RT = 78 - 1$

$RT = 77$

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Answer:

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Step-by-step explanation:

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