To reflect in the line y = -x + 6, we translate everything down 6 first. This will make it seem like we are reflecting in the line y = -x
(x,y) → (x, y-6)
Then, to reflect in the line y = -x, we switch the x- and y-coordinates and then make them negative
(x,y) → (-(y-6), -x)
Then we move everything back up again
(x,y) → (-(y-6), -x + 6)
I will present to you an example. Reflect the point (-4, 8) in the line y = -x + 6.
(-4,8) → (-(8-6), -(-4) + 6) → (-2, 10)
You should graph this out to confirm with the reflection line.
Itd be 50% hope this helps
Answer:
the range of the given data set is 5/8
Step-by-step explanation:
Range is the difference between the largest value in a number set minus the smallest value in a number set.
In this case, the largest value is 1 1/4 and the smallest is 5/8
We simply just subtract those 2 numbers to find the range.
- 1 1/4 - 5/8
- Find the common denominator
- 1 2/8 - 5/8
- Make the first fraction an improper fraction
- 10/8 - 5/8
- 5/8
Sin³ x-sin x=cos ² x
we know that:
sin²x + cos²x=1 ⇒cos²x=1-sin²x
Therefore:
sin³x-sin x=1-sin²x
sin³x+sin²x-sin x-1=0
sin³x=z
z³+z²-z-1=0
we divide by Ruffini method:
1 1 -1 -1
1 1 2 1 z=1
-------------------------------------
1 2 1 0
-1 -1 -1 z=-1
--------------------------------------
1 1 0 z=-1
Therefore; the solutions are z=-1 and z=1
The solutions are:
if z=-1, then
sin x=-1 ⇒x= arcsin -1=π+2kπ (180º+360ºK) K∈Z
if z=1, then
sin x=1 ⇒ x=arcsin 1=π/2 + 2kπ (90º+360ºK) k∈Z
π/2 + 2kπ U π+2Kπ=π/2+kπ k∈Z ≈(90º+180ºK)
Answer: π/2 + Kπ or 90º+180ºK K∈Z
Z=...-3,-2,-1,0,1,2,3,4....
This is unclear, I don't understand. Make it more clear.
