Answer:
17 nickles !
Step-by-step explanation:
First, identify the variables:
n = amount of nickels
d = amount of dimes
Next, setup the equations based on what you know. The first equation is:
n + d = 28
For the second equation, we know that a dime is worth 10¢ and a nickel is 5¢, so it should be:
0.05n + 0.10d = 1.95
This a three-step answer:
In one formula (you can use any of them; most people use the simplest one), single out the variable on one side
Apply the first formula into the second formula, and solve it to get the value of one variable
Apply the answer from the second formula into the first formula, and solve it to get the value of the other variable
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Step One:
n + d = 28
n + d - d = 28 - d
n = 28 - d
Step Two:
0.05n + 0.10d = 1.95
(0.05 * (28 - d)) + 0.10d = 1.95
1.40 - 0.05d + 0.10d = 1.95
1.40 + 0.05d = 1.95
1.40 - 1.40 + 0.05d = 1.95 - 1.40
0.05d = 0.55
d = 11
Step Three:
n = 28 - d
n = 28 - 11
n = 17
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Your answer should be 17 nickels and 11 dimes.
You can double check by applying the variables into both formulas.
n + d = 28
17 + 11 = 28
28 = 28
0.05n + 0.10d = 1.95
(0.05 * 17) + (0.10 * 11) = 1.95
0.85 + 1.10 = 1.95
1.95 = 1.95
I hope this helped.
For CO2 there is one atom of carbon and two atoms of oxygen. For H2O, there is one atom of oxygen and two atoms of hydrogen.
5+10+10+12+14+7= 58
x= 70-58
x=12 ft
Answer:
i.e. relation between speed-distance-time is one such situation that can be modeled using graph
Step-by-step explanation:
There are many real world examples that can be modeled using graph. Graphs are represented on co-ordinate planes, so any real world example that can be represented by use of linear equation can be represented onto a graph.
One such example, is speed-distance-time relation. Uniform speed can be represented on a graph as shown in figure.
So, the equation for speed is represented by equation as follows:
So, if we take distance on y axis and time on x axis with points as (distance,time)
(0,0) ==> 
(1,2) ==> 
(2,2) ==> 
the following points 0,0.5,1 will be plotted on graph. Similarly, more values can be plotted by assuming values for distance and time.
