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Helga [31]
3 years ago
13

How many solutions does the system of linear equations 6a + 3b = 12 and 6a - 3b = 12 have?

Mathematics
1 answer:
Olin [163]3 years ago
3 0

Answer:

One solution

Step-by-step explanation:

Lets solve it for b

3b= -6a+12

3b= 6a-12

Simplifying

b= -2a+4

b= 2a+4

Both have same slope and intercept hence both lines are going to intersect at one point. So the equations are having one solution.

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Find the volume of the triangular prism below.
brilliants [131]

Answer:

b.168

Step-by-step explanation:

6 0
3 years ago
Ubehebe crater in Death Valley has a diameter of a little more than 1/2 mile. If latisha walks around it's rim at a rate of 2 mi
Yuri [45]
Let's say that the diameter was 1/2 mile. So the diameter is 1/2,  then you need to find the circumference, aka perimeter of the circle. So 1/2 times 3.14 = 1.57 miles So then you would do 1.57/2 = .785 of an hour If you round to nearest tenth The answer is .8 of an hour.
8 0
3 years ago
Read 2 more answers
1) A school has 1600 students and they are going to vote as to whether they will completely convert the school completely off fo
fredd [130]

Answer:

Standard deviation of the students = 0.408

The students would you have to poll to be 95% confident of the outcome within /- 2% of the vote  

         = 0.408 X 1600

         = 652.8    

Step-by-step explanation:  

<u><em>Step(i):</em></u>-

Given sample size 'n' = 1600

95% confidence interval of the margin error is determined by

                      M.E = \frac{Z_{0.05} S.D}{\sqrt{n} }

Level of significance = 0.05

Z₀.₀₅ = 1.96

Given Margin of error = 2% = 0.02

       M.E = \frac{Z_{0.05} S.D}{\sqrt{n} }

       0.02 = \frac{1.96 X S.D}{\sqrt{1600} }

      0.02 X √1600 = 1.96 X S.D

       S.D = \frac{0.02X\sqrt{1600} }{1.96} = 0.408

Standard deviation of the students = 0.408

The students would you have to poll to be 95% confident of the outcome within /- 2% of the vote  

         = 0.408 X 1600

         = 652.8  

5 0
3 years ago
Suppose we are testing people to see if the rate of use of seat belts has changed from a previous value of 88%. Suppose that in
Andreas93 [3]

Answer:

a) We would expect to see 500*0.88=440

b) z=\frac{0.9 -0.88}{\sqrt{\frac{0.88(1-0.88)}{500}}}=1.376  

p_v =2*P(Z>1.376)=0.167  

So the p value obtained was a very high value and using the significance level assumed \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the true proportion is not significant different from 0.9.

The p value is a criterion to decide if we reject or not the null hypothesis, when p_v we reject the null hypothesis in other case we FAIL to reject the null hypothesis. And represent the "probability of obtaining the observed results of a test, assuming that the null hypothesis is correct".  

Step-by-step explanation:

Data given and notation

n=500 represent the random sample taken

X=450 represent the people that have the seat belt fastened

\hat p=\frac{450}{500}=0.9 estimated proportion of people that have the seat belt fastened

p_o=0.88 is the value that we want to test

\alpha represent the significance level

z would represent the statistic (variable of interest)

p_v{/tex} represent the p value (variable of interest)  Part aWe would expect to see 500*0.88=440Part bConcepts and formulas to use  We need to conduct a hypothesis in order to test the claim that the true proportion changes fro m 0.88.:  Null hypothesis:[tex]p=0.88  

Alternative hypothesis:p \neq 0.88  

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.9 -0.88}{\sqrt{\frac{0.88(1-0.88)}{500}}}=1.376  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level assumed is \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

p_v =2*P(Z>1.376)=0.167  

So the p value obtained was a very high value and using the significance level assumed \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the true proportion is not significant different from 0.9.

The p value is a criterion to decide if we reject or not the null hypothesis, when p_v we reject the null hypothesis in other case we FAIL to reject the null hypothesis. And represent the "probability of obtaining the observed results of a test, assuming that the null hypothesis is correct".  

8 0
3 years ago
8. Find the values of angles x, y,
Eddi Din [679]

Answer:

option A

Step-by-step explanation:

option A is the correct answer of this question.

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8 0
3 years ago
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