Answer:
1. y= 3x+7
2.y=1/2 x -1
Step-by-step explanation:
1.
Parallel lines have the same gradient.In the equation given,
y= 3x+5 , the slope is 3
So now, you find the equation of a line passing through point (-1,4) with m=3
m=Δ y/Δx
3= y-4/ x--1
3= y-4 /x+1
3(x+1) = y-4
3x+3 =y-4
3x+3+4=y
⇒⇒ y= 3x+7 is the equation.
2.
Two lines that are perpendicular to each other have the product of their slopes to be -1
Given equation to be y= -2x +8 then, m₁ = -2
Finding m₂ will be;
m₁ *m₂ = -1
-2 * m₂ = -1
-2 m₂ = -1
m₂ = -1/-2 = 1/2
So writing the equation of the perpendicular line with m₂ =1/2 , point (-4,-3)
will be;
m=Δy/Δx
1/2=y--3/x--4
1/2 = y+3/x+4
x+4 = 2( y+3)
x+4 = 2(y+3)
x+4 =2y+6
x+4-6=2y
x-2=2y
x/2 -2/2=y
y=1/2 x -1 is the equation.