A hyperbola with a center at (0, 0) can be defined as x²/a² − y²/b² = ±1.<span>
</span>The statement "<span>The symmetry of a hyperbola with a center at (h, k) only occurs at y = k" </span>is false, because a hyperbola have many different orientations.
It doesn't have to be symmetric about the lines y = k or x = h.
Answer:
maybe its not the right explanation cuz it doesnt make sense to me
Step-by-step explanation:
Answer:
its C so be quite please and
Answer:
1/3 or 0.333333
Step-by-step explanation:
The question talks about a die that was tossed once and we are now asked to find the probability that it is a figure greater than 4
---A die has 6 faces with the numbers 1,2,3,4,5 and 6 one on each of
the six faces.Considering an unbaised die the probability of any of the faces to appear in a single roll is 1/6.
So, P(1)=P(2)=P(3)=P(4)=P(5)=P(6)=1/6
Now that numbers greater than 4 are 5 and 6
So it can be P(5) or P(6)= P(5)+P(6)=2/6 = 1/3 or 0.33333
Answer 1/3 or 0.33333
Answer:
0.00013
Step-by-step explanation:
