<u>Given </u><u>:</u><u>-</u>
<u>To </u><u>Find</u><u> </u><u>:</u><u>-</u>
- To convert the given equation into standard form.
<u>Solution</u><u> </u><u>:</u><u>-</u>
As we know that the standard form of the line is ,
ax + by + c = 0
So the given equation is ,
y = 2/5x -1/3
y = 6x - 5/15
15y = 6x - 5
6x -15y -5 = 0
<u>Hence</u><u> the</u><u> required</u><u> </u><u>equation</u><u> of</u><u> the</u><u> line</u><u> is</u><u> </u><u>6</u><u>x</u><u> </u><u>-15y-5=</u><u>0</u><u>.</u>
A)line a and line b is your answer.
Answer:
Parallel lines are straight lines that don't ever touch. Think of a railroad track.
Perpendicular lines are lines that meet and make a 90 degree angle
F(-3) = 8
Plug -3 into x and just solve it.
Answer:
The first answer is correct.
(x + 1)^2 + (y - 2)^2 = 1
A circle with the midpoint M(Mx, My) and the radius r can be written as
(x - Mx)^2 + (y - My)^2 = r^2
