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NemiM [27]
3 years ago
6

Solve the inequality -5/4(8x+4)<6-3x. Show your work.

Mathematics
2 answers:
Oxana [17]3 years ago
4 0

Answer:

x > -11/7

Step-by-step explanation:

-10x - 5 < 6 - 3x

-5 -6 < -3x + 10x

7x > -11

x > -11/7

Debora [2.8K]3 years ago
3 0

Answer:

x>-\frac{11}{7}

Step-by-step explanation:

<u>Step 1:  Distribute</u>

<u />-\frac{5}{4} (8x+4)

(-\frac{5}{4} *8x)+(-\frac{5}{4} *4)

-\frac{40x}{4}-\frac{20}{4}

-10x-5

<u>Step 2:  Add 10x to both sides</u>

<u />-10x-5\mathbf{+10x}

-5

<u>Step 3:  Subtract 6 from both sides</u>

<u />-5\mathbf{-6}

-11

<u>Step 4:  Divide both sides by 7</u>

<u />-11\mathbf{/7}

x>-\frac{11}{7}

Answer:  x>-\frac{11}{7}

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Kryger [21]

Answer:

1)

Given the triangle RST with Coordinates  R(2,1), S(2, -2) and T(-1 , -2).

A dilation is a transformation which produces an image that is the same shape as original one, but is different size.  

Since, the scale factor \frac{5}{3} is greater than 1, the image is enlargement or a stretch.  

Now, draw the dilation image of the triangle RST with center (2,-2) and scale factor \frac{5}{3}

Since, the center of dilation at S(2,-2) is not at the origin, so the point S and its image S{}' are same.

Now, the distances from the center of the dilation at point S to the other points R and T.  

The dilation image will be\frac{5}{3} of each of these distances,

SR=3, so S{}'R{}'=5 ;


ST=3, so S{}'T{}'=5  

Now, draw the image of RST i.e R'S'T'

Since, RT=3\sqrt{2} [By using hypotenuse of right angle triangle] and R{}'T{}'=5\sqrt{2}.


2)

(a)

Disagree with the given statement.

Side Angle Side postulate (SAS) states that:

If two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle then these two triangles are congruent.

Given: B is the midpoint of \overline{AC} i.e \overline{AB}\cong \overline{BC}

In the triangle ABD and triangle CBD, we have

\overline{AB}\cong \overline{BC}   (SIDE)            [Given]

\overline{BD}\cong \overline{BD}   (SIDE)            [Reflexive post]

Since, there is no included angle in these triangles.

∴ \Delta ABD is not congruent to \Delta CBD .

Therefore, these triangles does not follow the SAS congruence postulates.

(b)

SSS(SIDE-SIDE-SIDE) states that if three sides of one triangle are congruent to three sides of another triangle, then the triangles are congruent.

Since it is also given that  \overline{AD}\cong \overline{CD}.

therefore, in the triangle ABD and triangle CBD, we have

\overline{AB}\cong \overline{BC}   (SIDE)            [Given]

\overline{AD}\cong \overline{CD}   (SIDE)           [Given]

\overline{BD}\cong \overline{BD}   (SIDE)            [Reflexive post]

therefore by, SSS postulates \Delta ABD\cong \Delta CBD.

3)

Given that:  \angle1=\angle 3 are vertical angles, as they are formed by intersecting lines.

Therefore

, by the definition of linear pairs

\angle 1 and \angle 2 and \angle 3  and \angle 2 are linear pair.

By linear pair theorem, \angle 1 and \angle 2   are supplementary, \angle 2 and \angle 3  are supplementary.

m\angle1+m\angle 2=180^{\circ}

m\angle2+m\angle 3=180^{\circ}

Equate the above expressions:

m\angle 1+m\angle 2=m\angle 2+m\angle 3

Subtract the angle 2 from both sides in the above expressions

∴m\angle 1=m\angle 3

By Congruent Supplement theorem: If two angles are supplements of the same angle, then the two angles are congruent.


therefore, \angle 1\cong \angle 3.















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The school store sells erasers for $0.35 each and pencils for $0.15 each. Anthony spent $2.80 to buy a total of 12 erasers and p
Sergio039 [100]

Answer:

5 erasers.

Step-by-step explanation:

0.35e + 0.15p = 2.80

e + p = 12

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4.2 - 0.35p + 0.15p = 2.80

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e = 12 - 7

e = 5

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3 years ago
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