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Naddik [55]
2 years ago
10

Clara and Tyler are working on an activity in class. Clara says that 17 + (−6) and (−6) + 17 have the same value. Tyler says tha

t 8 + (−8) and (−8) + (−8) have the same value. Who is correct? Explain your reasoning
Mathematics
1 answer:
ELEN [110]2 years ago
6 0

Answer: When there are two of the same signs when adding and multiplying it means they are positive but two of the same are negative, which means Clara is rights.

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bess has knitted 5/8 of the scarf she is making. has she knitted more than 1/2 of the scarf. hint: find an equivalent fraction i
Mashcka [7]
Yes half of 8 is 4 equaling 4/8. Since she knitted 5/8, then she knitted more than 1/2. Hope this helps:)
4 0
3 years ago
Read 2 more answers
Which of these shapes is congruent to the given shape?
NeTakaya

Answer: It’s c

Step-by-step explanation:

6 0
3 years ago
Prove that the value of the expression: 731^2−631^2 is divisible by 100
Ivanshal [37]

Answer:

Step-by-step explanation:

731² - 631² is the difference of squares.

731² - 631² = (731+631)(731-631) = 1362×100

therefore, 731² - 631² is divisible by 100

7 0
3 years ago
Chapter one course 2
Marysya12 [62]
What you need help with
8 0
3 years ago
If
Leno4ka [110]

Answer:

\frac{s^2-25}{(s^2+25)^2}

Step-by-step explanation:

Let's use the definition of the Laplace transform and the identity given:\mathcal{L}[t \cos 5t]=(-1)F'(s) with F(s)=\mathcal{L}[\cos 5t].

Now, F(s)=\int_0 ^{+ \infty}e^{-st}\cos(5t) dt. Using integration by parts with u=e^(-st) and dv=cos(5t), we obtain that F(s)=\frac{1}{5}\sin(5t)e^{-st} |_{0}^{+\infty}+\frac{s}{5}\int_0 ^{+ \infty}e^{-st}\sin(5t) dt=\int_0 ^{+ \infty}e^{-st}\sin(5t) dt.

Using integration by parts again with u=e^(-st) and dv=sin(5t), we obtain that

F(s)=\frac{s}{5}(\frac{-1}{5}\cos(5t)e^{-st} |_{0}^{+\infty}-\frac{s}{5}\int_0 ^{+ \infty}e^{-st}\sin(5t) dt)=\frac{s}{5}(\frac{1}{5}-\frac{s}{5}\int_0^{+ \infty}e^{-st}\sin(5t) dt)=\frac{s}{5}-\frac{s^2}{25}F(s).

Solving for F(s) on the last equation, F(s)=\frac{s}{s^2+25}, then the Laplace transform we were searching is -F'(s)=\frac{s^2-25}{(s^2+25)^2}

3 0
3 years ago
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