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MrRa [10]
3 years ago
9

A number increased by 100% and decreased by 20% is x. what is the number ? NEEDED TODAY

Mathematics
2 answers:
vodka [1.7K]3 years ago
5 0

Answer:

Let's assume the number be 100.

According to the problem , 100 is increased by 100%.

So, new number will be 100+100=200

Now 200 will decreased by 20%.

So, 20% of 200= 0.20*200= 40.

So, again the number has been changed into 200+40=240.

So, x=240

Step-by-step explanation:

madreJ [45]3 years ago
4 0

9514 1404 393

Answer:

  x/1.6

Step-by-step explanation:

Let n represent the number. When n is increased by 100%, its new value is ...

  n(1 +100%) = n(1 +1) = 2n

When this value is decreased by 20%, its new value is ...

  (2n)(1 -20%) = (2n)(0.8) = 1.6n

This value is x, so the number is ...

  1.6n = x

  n = x/1.6 . . . . . . . divide both sides by 1.6

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Q.6. The equation of the ellipse whose centre is at the origin and the x-axis, the major axis, which passes
azamat

<h3>Answer:</h3>

Equation of the ellipse = 3x² + 5y² = 32

<h3>Step-by-step explanation:</h3>

<h2>Given:</h2>

  • The centre of the ellipse is at the origin and the X axis is the major axis

  • It passes through the points (-3, 1) and (2, -2)

<h2>To Find:</h2>

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<h2>Solution:</h2>

The equation of an ellipse is given by,

\sf \dfrac{x^2}{a^2} +\dfrac{y^2}{b^2} =1

Given that the ellipse passes through the point (-3, 1)

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\sf \dfrac{(-3)^2}{a^2} +\dfrac{1^2}{b^2} =1

Cross multiplying we get,

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Multiply by 4 on both sides,

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Also by given the ellipse passes through the point (2, -2)

Substituting this,

\sf \dfrac{2^2}{a^2} +\dfrac{(-2)^2}{b^2} =1

Cross multiply,

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Subtracting equations 2 and 1,

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  • 3a² = 32
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Substituting in 2,

  • 32/3 × b² = 4b² + 4 × 32/3
  • 32/3 b² = 4b² + 128/3
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Substituting the values in the equation for ellipse,

\sf \dfrac{x^2}{32/3} +\dfrac{y^2}{32/5} =1

\sf \dfrac{3x^2}{32} +\dfrac{5y^2}{32} =1

Multiplying whole equation by 32 we get,

3x² + 5y² = 32

<h3>Hence equation of the ellipse is 3x² + 5y² = 32</h3>
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