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3 years ago

A number increased by 100% and decreased by 20% is x. what is the number ? NEEDED TODAY

Mathematics

2 answers:

vodka [1.7K]3 years ago

5 0

Answer:

Let's assume the number be 100.

According to the problem , 100 is increased by 100%.

So, new number will be 100+100=200

Now 200 will decreased by 20%.

So, 20% of 200= 0.20*200= 40.

So, again the number has been changed into 200+40=240.

So, x=240

Step-by-step explanation:

madreJ [45]3 years ago

4 0

9514 1404 393

Answer:

x/1.6

Step-by-step explanation:

Let n represent the number. When n is increased by 100%, its new value is ...

n(1 +100%) = n(1 +1) = 2n

When this value is decreased by 20%, its new value is ...

(2n)(1 -20%) = (2n)(0.8) = 1.6n

This value is x, so the number is ...

1.6n = x

n = x/1.6 . . . . . . . divide both sides by 1.6

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3 years ago

In a particular course, it was determined that only 70% of the students attend class on Fridays. From past data it was noted tha

siniylev [52]

Answer: Probability that students who did not attend the class on Fridays given that they passed the course is 0.043.

Step-by-step explanation:

Since we have given that

Probability that students attend class on Fridays = 70% = 0.7

Probability that who went to class on Fridays would pass the course = 95% = 0.95

Probability that who did not go to class on Fridays would passed the course = 10% = 0.10

Let A be the event students passed the course.

Let E be the event that students attend the class on Fridays.

Let F be the event that students who did not attend the class on Fridays.

Here, P(E) = 0.70 and P(F) = 1-0.70 = 0.30

P(A|E) = 0.95, P(A|F) = 0.10

We need to find the probability that they did not attend on Fridays.

We would use "Bayes theorem":

$P(F\mid A)=\dfrac{P(F).P(A\mid F)}{P(E).P(A\mid E)+P(F).P(A\mid F)}\\\\P(F\mid A)=\dfrac{0.30\times 0.10}{0.70\times 0.95+0.30\times 0.10}\\\\P(F\mid A)=\dfrac{0.03}{0.695}=0.043$

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3 years ago