<h3>SO, WHERE IS YOUR QUESTION?</h3>
BTW,,


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C
If you plug in the values in that equation, it works.
Answer:
The exam was out of 75.
Step-by-step explanation:
You know that he earned 65% so more than half his answers were correct.
Then, you would guess and check try 49/60, 49/70, and go up by 10s or 5s. You will then realize that 49÷75 equals 65.333. This rounds up to 65.
Given that JKLM is a rhombus and the length of diagonal KM=10 na d JL=24, the perimeter will be found as follows;
the length of one side of the rhombus will be given by Pythagorean theorem, the reason being at the point the diagonals intersect, they form a perpendicular angles;
thus
c^2=a^2+b^2
hence;
c^2=5^2+12^2
c^2=144+25
c^2=169
thus;
c=sqrt169
c=13 units;
thus the perimeter of the rhombus will be:
P=L+L+L+L
P=13+13+13+13
P=52 units
Answer:
12
Step-by-step explanation:
The square root of 144 = 12.
12 x 12 = 144
Hope that helps!