We have been given in a cohort of 35 graduating students, there are three different prizes to be awarded. We are asked that in how many different ways could the prizes be awarded, if no student can receive more than one prize.
To solve this problem we will use permutations.
We know that formula for permutations is given as
On substituting the given values in the formula we get,
Therefore, there are 39270 ways in which prizes can be awarded.
Answer:
the linear approximation formula is based on the equation of the tangent line of a function at a fixed point. The linear approximation of a function f(x) at a fixed value x = a is given by L(x) = f(a) + f '(a) (x - a).
Step-by-step explanation:
Answer:
Reduced fraction: 14/25
Step-by-step explanation:
To write 0.56 in terms of fractions we need to multiply and divide the number by 100:
(0.56 * 100)/100 = 56/100. Then we simplify the fraction by dividing the numerator and denominator by the common factor 2 as many times as possible:
56/100 = 28/50 = 14/25
The fraction 14/25 cannot be more simplified
8+~1-3=4
Explanation-
8-1 is the same as 8+~1 so=7
7-3=4
Answer:
-2 and -3
Step-by-step explanation:
Let L represent the large integer and S represent the smaller integer
Given Large Integer = 10 + 4 times Smaller Integer
Mathematically:
L = 10 + 4S -------eq 1
It is also given that the integers are consecutive,
hence L = S + 1------ eq2
Now we can solve a system of equations by substitution.
Substitute eq 2 into eq 1
S + 1 = 10 + 4S (subtract 1 from both sides)
S = 10 - 1 + 4S
S = 9 + 4S (subtract 4S from both sides)
S - 4S = 9
-3S = 9 (divide both sides by -3)
S = 9 / (-3) = -3 (answer)
form equation 2,
L = S + 1
L = -3 + 1
L = -2 (answer)
