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Mathematics

2 answers:

lesantik [10]3 years ago

6 0

Answer:

Step-by-step explanation:

Novosadov [1.4K]3 years ago

4 0

Ok firstly convert the first equation into the understandable form.
y = -2x +3

Next draw a dot on the y-ax at the height of +3 (3 is c in (y = ax + c) and c is always the intersection with the y-ax).

Next substitute y with 0,
0 = -2x + 3
<=> x = 3/2
Draw a dot on the x-ax at x=3/2 or 1.5.
Connect the two dots and you have the first function.

Now do the same thing for the second equation and read the coordinates from the intersection of the two equations.

That’s it!

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What is tje equation for the linear function whose graph contains the points (2,5) and (3,0) ?

dolphi86 [110]

In order to find a slope, there is an equation:

Y2-Y1/X2-X1

X1=2
X2=3
Y1=5
Y2=0

0-5= -5
3-2=1

Since slope is written as Y/X, slope would be-5/1 or simply, -5.

Now, we need to find the y-intercept.

To do this, shift the original equation:

Original equation: y=-5x+b

Shifted equation: b=y+5x

Now, plug in one of the points.

Let's use (2,5)

b=5+5(2)

5*2=10
10+5=15

y-intercept=15

So, the full equation of the line would be:

y=-5x+15

4 0

3 years ago

Differentiate: y=152+26−37 dy/dx= answer

ozzi

Answer:

$\frac{dy}{dx} y=0$