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hoa [83]
3 years ago
13

Please do all four, thanks :) I'm feeling generous today *40 points*

Mathematics
2 answers:
MrMuchimi3 years ago
8 0

Step-by-step explanation:

A. x^2-9x+18

B. x^2-8x+16

C. 2x^2-5x-12

D. 12x^2-31x+7

Lady bird [3.3K]3 years ago
5 0

Answer:

I answered my own brainly question :)

Step-by-step explanation:

Hi

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Express ratio 3.5:14 as 1:n
Luba_88 [7]

Answer:

1 : 4

Step-by-step explanation:

3.5 : 14 ( divide both parts by 3.5 )

= 1 : 4

3 0
1 year ago
Lester and kari are playing a number pattern game. kari wrote the following pattern. 45.5,49,52.5,__,59.5
Anit [1.1K]
The answer is going to be 3.5 more than 52.5 so the answer is 56.
7 0
3 years ago
Please help! calculate the maximum volume of the box.
lina2011 [118]
Have you used the length*width*height?
8 0
3 years ago
A) Write the sequence of natural numbers which are multiplied by 3 ?
Volgvan

Answer:

a) 3, 6, 9, 12, 15,...,3\cdot n, b) 4, 7, 10, 13, 16,...,3\cdot n +1, c) Both sequences are arithmetic.

Step-by-step explanation:

a) The sequence of natural numbers which are multiplied by 3 are represented by the function f(n) = 3\cdot n, n\in \mathbb{N}. Let see the first five elements of the sequence: 3, 6, 9, 12, 15,...

b) The sequence of natural numbers which are multiplied by 3 and added to 1 is represented by the function f(n) = 3\cdot n + 1, n\in \mathbb{N}. Let see the first five elements of the sequence: 4, 7, 10, 13, 16,...

c) Both sequences since differences between consecutive elements is constant. Let prove this statement:

(i) f(n) = 3\cdot n

\Delta f = f(n+1) -f(n)

\Delta f = 3\cdot (n+1) -3\cdot n

\Delta f = 3

(ii) f(n) = 3\cdot n +1

\Delta f = f(n+1)-f(n)

\Delta f = [3\cdot (n+1)+1]-(3\cdot n+1)

\Delta f = 3

Both sequences are arithmetic.

8 0
2 years ago
a car purchased for $34,000 is expected to lose value, or depreciate, at a rate of 6% per year.using x for years and y for the v
Vika [28.1K]

Answer:

y = 34000(1-0.06) ^ t

After 7.40 years it will be worth less than 21500

Step-by-step explanation:

This problem is solved using a compound interest function.

This function has the following formula:

y = P(1-n) ^ t

Where:

P is the initial price = $ 34,000

n is the depreciation rate = 0.06

t is the elapsed time

The equation that models this situation is:

y = 34000(1-0.06) ^ t

Now we want to know after how many years the car is worth less than $ 21500.

Then we do y = $ 21,500. and we clear t.

21500 = 34000(1-0.06) ^ t\\\\log(21500/34000) = tlog(1-0.06)\\\\t = \frac{log(21500/34000)}{log(1-0.06)}\\\\t = 7.40\ years.

After 7.40 years it will be worth less than 21500

3 0
3 years ago
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