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Let the length of second side be x" ,
So,
Length of first side = 2" shorter than second = ( x - 2 )"
Length of third side = 5" longer than second = ( x + 5 )"
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Given, perimeter = 33"
= > first side + second side + third side = 33"
= > ( x - 2 ) + x + ( x + 5 ) = 33
= > x - 2 + x + x + 5 = 33
= > 3x + 3 = 33
= > 3x = 30
= > x = 10
Hence, length of each side is
First side = ( x - 2 )" = ( 10 - 2 )" = 8 inches
Second side = x " = 10 inches
Third side = ( x + 5 )" = ( 10 + 5 )" = 15 inches
So,
Length of first side = 2" shorter than second = ( x - 2 )"
Length of third side = 5" longer than second = ( x + 5 )"
=×=×=×=×=×=×=×=×=×=×=×=×=×=×=×=×=
Given, perimeter = 33"
= > first side + second side + third side = 33"
= > ( x - 2 ) + x + ( x + 5 ) = 33
= > x - 2 + x + x + 5 = 33
= > 3x + 3 = 33
= > 3x = 30
= > x = 10
Hence, length of each side is
First side = ( x - 2 )" = ( 10 - 2 )" = 8 inches
Second side = x " = 10 inches
Third side = ( x + 5 )" = ( 10 + 5 )" = 15 inches