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dmitriy555 [2]
4 years ago
7

What is the solution to this system of linear equations? 2x + y = 1 3x – y = –6 (–1, 3) (1, –1) (2, 3) (5, 0)

Mathematics
2 answers:
Mandarinka [93]4 years ago
4 0
The answer is (-1,3).
Pavlova-9 [17]4 years ago
3 0

Answer:

(-1, 3)

Step-by-step explanation:

We have two equations:

2x+y=1\\3x-y=-6

Adding the two linear equations:

(2x+3x)+(y-y)=1+(-6)

Simplifying

5x+0y=1-6

5x=-5\\

Clearing for x:

x=\frac{-5}{5} \\x=-1

Now we substitute this value of x in either of the two initial equations to find the value of y, Substituting in the first one:

2x+y=1\\2(-1)+y=1\\-2+y=1\\y=1+2\\y=3

the answer is (-1, 3) because x=-1 and y=3

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The mean would be 4.5. This is because you add up all the numbers which equals 22.5. Then divide by 5 since there is 5 numbers in the set. So the answer comes out to be 4.5.
3 0
3 years ago
IL<br> 8x-9<br> 5x-3<br> What’s x
shepuryov [24]

Step-by-step explanation:

8x-9=5x-3

Move any equation to the opposite side. I'll use the left this time

8x - 8x - 9 + 9 = 5x - 8x - 3 + 9

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4 years ago
2/3 - 10/9and5/3 and 7/9
agasfer [191]

Step-by-step explanation:

always Pythagoras with the coordinate differences as sides and the distance the Hypotenuse.

c² = (2/3 - 5/3)² + (-10/9 - -7/9)² = (-3/3)² + (-10/9 + 7/9)² =

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7 0
3 years ago
Read 2 more answers
PLEASEE HELPPP MEE!!<br> What is the measure of angle 3?
polet [3.4K]

Answer:

71

Step-by-step explanation:

angle 3, and the 24 degree and 85 degree angle are supplementary angles, which mean they add up to 180. Subtract 24 and 85 from 180 to find angle 3 :)

7 0
3 years ago
13. How many distinct 4-letter groupings can be made with the letters from the word champion if letters may not be repeated?
ddd [48]

Answer:

N = 1680

Therefore, 1680 '4 letter groupings' can be formed from the word 'champion'

Step-by-step explanation:

Given the word 'champion' which is an 8 distinct Letter word. The number of 4 letter groupings that could be formed from it can be given by the permutation since in this case order of letters are important.

The number of distinct 4 letter groupings can be given as;

N = nPr = 8!/(8-4)!, where n= 8 and r = 4

N = 8P4 = 8!/(8-4)!

N= 8!/4!

N = 1680

Therefore, 1680 '4 letter groupings' can be formed from the word 'champion'

7 0
4 years ago
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