Question

What is the solution to this system of linear equations? 2x + y = 1 3x – y = –6 (–1, 3) (1, –1) (2, 3) (5, 0)

Answer 1

The answer is (-1,3).

Answer 2

Answer:

$(-1, 3)$

Step-by-step explanation:

We have two equations:

$2x+y=1\\3x-y=-6$

Adding the two linear equations:

$(2x+3x)+(y-y)=1+(-6)$

Simplifying

$5x+0y=1-6$

$5x=-5$

Clearing for $x$:

$x=\frac{-5}{5} \\x=-1$

Now we substitute this value of $x$ in either of the two initial equations to find the value of $y$, Substituting in the first one:

$2x+y=1\\2(-1)+y=1\\-2+y=1\\y=1+2\\y=3$

the answer is $(-1, 3)$ because $x=-1$ and $y=3$