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Setler79 [48]
3 years ago
10

A ‘can-chiller’ is used to make a can of drink colder. The initial temperature of the liquid in the can was 25.0 °C. The can-chi

ller decreased the temperature of the liquid to 20.0 °C. The amount of energy transferred from the liquid was 6930 J. The mass of liquid in the can was 0.330 kg.
Calculate the specific heat capacity of the liquid. Give the unit.

Please help :)
Physics
1 answer:
Helen [10]3 years ago
6 0

Answer:

4200 J/°C/kg

Explanation:

The formula for heat transfer is given by :

Q= m*c*ΔT  where;

Q= heat transferred = 6930 J

m=mass of the liquid = 0.330 kg

c= specific heat capacity=?

ΔT = 25-20 = 5.0°C

Applying the values in the formula as;

Q= m*c*ΔT

6930 = 0.330 * c * 5

6930 = 1.65 c

6930/1.65 = c

4200 = c

c= 4200 J/°C/kg

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Answer:

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given data

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time t3 = 1 min = 60 s

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to find out

displacement in m  and average speed and  average velocity

solution

so we find here displacement

displacement = vt    .............1

so

displacement 1 = 24 × 180 =  4220 m south = -4220 j   ..........2

displacement 2 = 25 × 132 = 3300 m west = -3300 i     ...........3

distance 3 = 30 × 60 =  1800 m

displacement   = 1800 cos45 -i + 1800 cos45 j

displacement   = -1272.79 i + 1272.79 j                             .............4

so total displacement D =  equation 2 + equation 3 + equation 4

total displacement D =  -4220 j -3300 i -1272.79 i + 1272.79 j

total displacement D =  -2947.21 j - 4572.79 i

so magnitude m = √(-2947.21)² + (-4572.79)² )

so magnitude m = 5440.26 M

and

average speed is = total distance / time

average speed is = (4220 + 3300+ 1800 ) / 372

average speed is = 25.05 m/s

and

average velocity = total displacement / time

average velocity = 5440.26 / 372

average velocity = 14.62 m/s

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