Ask question

Ask question

All categories

Murljashka [212]

3 years ago

8

a block is 2cm wide, 5.4cm deep, and 3.1cm long. the density of the block is 8.5g/cm. what is the mass of the blocks?

1 answer:

Allushta [10]3 years ago

3 0

We know, density = mass / volume
Here, d = 8.5 g/cm³
v = 2 * 5.4 * 3.1 = 33.48 cm³

Substitute their values,
m = 8.5 * 33.48
m = 284.58 g

In short, Your Answer would be 284.58 g

Hope this helps!

You might be interested in

What Energy source that produces wind

svetoff [14.1K]

Wind is usually caused by a difference in pressure that causes wind to be "Pushed" on the surface of earth. Air usually moves from high to low pressure and that is what we call wind. Please hit the thanks button if this helped :)

6 0

2 years ago

Read 2 more answers

A force can affect the _____ of an object.

BARSIC [14]

Flow. such as running into something or friction

Flow Final Answer

7 0

2 years ago

Read 2 more answers

A voltage source provides ___________ required for electric current.

Gnoma [55]

Two terminal device which can maintain a fixed voltage. Hope this help I need more detail in your question this is all I can provide. :)

8 0

2 years ago

Calculate the de Broglie wavelength of: a) A person running across the room (assume 180 kg at 1 m/s) b) A 5.0 MeV proton

solmaris [256]

Answer:

a

$\lambda = 3.68 *10^{-36} \ m$

b

$\lambda_p = 1.28*10^{-14} \ m$

Explanation:

From the question we are told that

The mass of the person is $m = 180 \ kg$

The speed of the person is $v = 1 \ m/s$

The energy of the proton is $E_ p = 5 MeV = 5 *10^{6} eV = 5.0 *10^6 * 1.60 *10^{-19} = 8.0 *10^{-13} \ J$

Generally the de Broglie wavelength is mathematically represented as

$\lambda = \frac{h}{m * v }$

Here h is the Planck constant with the value

$h = 6.62607015 * 10^{-34} J \cdot s$

So

$\lambda = \frac{6.62607015 * 10^{-34}}{ 180 * 1 }$

=> $\lambda = 3.68 *10^{-36} \ m$

Generally the energy of the proton is mathematically represented as

$E_p = \frac{1}{2} * m_p * v^2_p$

Here $m_p$ is the mass of proton with value $m_p = 1.67 *10^{-27} \ kg$

=> $8.0*10^{-13} = \frac{1}{2} * 1.67 *10^{-27} * v^2$

=> $v _p= \sqrt{\frac{8.0 *10^{-13}}{ 0.5 * 1.67 *10^{-27}} }$

=> $v = 3.09529 *10^{7} \ m/s$

So

$\lambda_p = \frac{h}{m_p * v_p }$

so $\lambda_p = \frac{6.62607015 * 10^{-34}}{1.67 *10^{-27} * 3.09529 *10^{7} }$

=> $\lambda_p = 1.28*10^{-14} \ m$

5 0

3 years ago

Which object will have the most potential energy?

Svetradugi [14.3K]

Answer: the most potential energy == 5 kg book, 2 m from the ground= 98 Joules

Explanation:

potential energy = m g h

m = mass

g = acceleration due gravity = 9.8 m/s²

h = distance above ground

1. Pe₁ = 1 kg x 2 m x g = 2 g

2. Pe₂ = 5 kg x 2 m x g = 10 g = 10 kg m x 9,8 m/s² = 98 Joules

3. Pe₃ = 1 kg x 0,5 m x g = 0,5 g

4. Pe₄ = 5 kg x 0.5 m x g = 2,5 g

10 > 2,5 > 2 >0,5

5 0

2 years ago