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chubhunter [2.5K]
3 years ago
14

HELP!!! ITS TIMED!!!! Please explain the answer!!

Mathematics
1 answer:
jeka57 [31]3 years ago
5 0
(X+2)(y+3) I don’t know how to explain my Brian just knows that! Lol
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B is a number larger than 1
Ulleksa [173]
B is greater than 1, so B>1
3 0
3 years ago
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There are 26 third graders and 32 fourth graders going on a field trip. Each van can carry 10 people
3241004551 [841]

No question was asked buy i'll try to answer anyway.

either im assuming its asking how many vans or how many missing seats.

26+32 58 students total,

You would need 6 vans to carry them, and 2 seats would be missing.

If this isnt what you were looking for please comment a question and i'll try to help

5 0
3 years ago
3 3/5 times negative 8 1/3
Vesna [10]
-30 is the answer to your problem.
6 0
3 years ago
13. Suppose the probability of passing a driving test is 65%. (a) On a certain afternoon 15 people are tested. (i) What is the e
Alex_Xolod [135]

Answer: 9

Step-by-step explanation:

Based on the information given in the question, the expected number of people who pass will be calculated as:

= Probability of passing the driving test × Number of people tested

= 65% × 15

= 0.65 × 15

= 9.75

Therefore, expected number of people who pass is 9.

8 0
3 years ago
Let A, B, C and D be sets. Prove that A \ B and C \ D are disjoint if and only if A ∩ C ⊆ B ∪ D
ANEK [815]

Step-by-step explanation:

We have to prove both implications of the affirmation.

1) Let's assume that A \ B and C \ D are disjoint, we have to prove that A ∩ C ⊆ B ∪ D.

We'll prove it by reducing to absurd.

Let's suppose that A ∩ C ⊄ B ∪ D. That means that there is an element x that belongs to A ∩ C but not to B ∪ D.

As x belongs to A ∩ C, x ∈ A and x ∈ C.

As x doesn't belong to B ∪ D, x ∉ B and x ∉ D.

With this, we can say that x ∈ A \ B and x ∈ C \ D.

Therefore, x ∈ (A \ B) ∩ (C \ D), absurd!

It's absurd because we were assuming that A \ B and C \ D were disjoint, therefore their intersection must be empty.

The absurd came from assuming that A ∩ C ⊄ B ∪ D.

That proves that A ∩ C ⊆ B ∪ D.

2) Let's assume that A ∩ C ⊆ B ∪ D, we have to prove that A \ B and C \ D are disjoint (i.e.  A \ B ∩ C \ D is empty)

We'll prove it again by reducing to absurd.

Let's suppose that  A \ B ∩ C \ D is not empty. That means there is an element x that belongs to  A \ B ∩ C \ D. Therefore, x ∈ A \ B and x ∈ C \ D.

As x ∈ A \ B, x belongs to A but x doesn't belong to B.  

As x ∈ C \ D, x belongs to C but x doesn't belong to D.

With this, we can say that x ∈ A ∩ C and x ∉ B ∪ D.

So, there is an element that belongs to A ∩ C but not to B∪D, absurd!

It's absurd because we were assuming that A ∩ C ⊆ B ∪ D, therefore every element of A ∩ C must belong to B ∪ D.

The absurd came from assuming that A \ B ∩ C \ D is not empty.

That proves that A \ B ∩ C \ D is empty, i.e. A \ B and C \ D are disjoint.

7 0
3 years ago
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