![(\sqrt[5]{x^{7}})^{3}=(x^{\frac{7}{5}})^{3}=x^{\frac{7\cdot3}{5}}=x^{\frac{21}{5}}](https://tex.z-dn.net/?f=%28%5Csqrt%5B5%5D%7Bx%5E%7B7%7D%7D%29%5E%7B3%7D%3D%28x%5E%7B%5Cfrac%7B7%7D%7B5%7D%7D%29%5E%7B3%7D%3Dx%5E%7B%5Cfrac%7B7%5Ccdot3%7D%7B5%7D%7D%3Dx%5E%7B%5Cfrac%7B21%7D%7B5%7D%7D)
The root is equivalent to a fractional power with that number as the denominator. Otherwise, the rules of exponents apply.
Hello user
To solve for V we simplify both sides of the equation then isolate the variable to get v <span>≥ 2
Therefor the answer is: </span>v ≥ 2
<span>
I hope this helped
-Chris</span>
Answer:
Hey! I believe this is your answer:
11094%
Step-by-step explanation:
Answer: Equilateral triangles.
Explanation: We know that in similar polygons, its all the corresponding angles are congruent. Only the set of equilateral triangles contains members that are always similar( by AAA similarity criteria) to one another as the measure of all the angles of equilateral triangle is fixed i.e. 60°.
Rest other do not have fixed measure for angles in it.
