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valentina_108 [34]
3 years ago
13

What was the price of Caleb's groceries, before tax?

Mathematics
1 answer:
elixir [45]3 years ago
4 0

Answer:

Caleb bought groceries and paid \$1.60$1.60dollar sign, 1, point, 60 in sales tax. The sales tax rate is 2.5\%2.5%2, point, 5, percent. What was the price of Caleb's groceries, before tax

Step-by-step explanation:

This is all I know~

Hope it helps!

Good luck with your work!!~

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Can someone help me!<br> if something cost $4.90 due to a 14% discount what is the original price
Vlad [161]

Answer:

$4.21

Step-by-step explanation:

Discount = Original Price x Discount %/100

Discount = 4.9 × 14/100

Discount = 4.9 x 0.14

You save = $0.69

Final Price = Original Price - Discount

Final Price = 4.9 - 0.686

Final Price = $4.21

6 0
3 years ago
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Allisa [31]

Answer:

320,000

Step-by-step explanation:

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3 years ago
Suppose the horses in a large stable have a mean weight of 975lbs, and a standard deviation of 52lbs. What is the probability th
Lubov Fominskaja [6]

Answer:

0.8926 = 89.26% probability that the mean weight of the sample of horses would differ from the population mean by less than 15lbs if 31 horses are sampled at random from the stable

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 975, \sigma = 52, n = 31, s = \frac{52}{\sqrt{31}} = 9.34

What is the probability that the mean weight of the sample of horses would differ from the population mean by less than 15lbs if 31 horses are sampled at random from the stable?

pvalue of Z when X = 975 + 15 = 990 subtracted by the pvalue of Z when X = 975 - 15 = 960. So

X = 990

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{990 - 975}{9.34}

Z = 1.61

Z = 1.61 has a pvalue of 0.9463

X = 960

Z = \frac{X - \mu}{s}

Z = \frac{960 - 975}{9.34}

Z = -1.61

Z = -1.61 has a pvalue of 0.0537

0.9463 - 0.0537 = 0.8926

0.8926 = 89.26% probability that the mean weight of the sample of horses would differ from the population mean by less than 15lbs if 31 horses are sampled at random from the stable

7 0
3 years ago
How you divide a decimal
Tom [10]
Easy you just divide it like a regular then put move the decimal to the left the number of times letters are behind it.
8 0
3 years ago
A worker's wage (w) is directly proportional to the number of hours (h) worked. If $71.25 is earned for working 5 h, how much is
marissa [1.9K]

Answer:

The amount earned is $327.75

Step-by-step explanation:

If the workwr working for 5h gets $71.25, then his working for 1 hour could be said to be x.

5h = $71.25

1h = x; cross multiplying would result in

x= \frac{($71.25*1)}{5h}

x= $14.25 which is the pay for 1h

Therefore for 23 h the worker would earn

23* 14.25 = $327.75

5 0
3 years ago
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