Answer: B. x ~ B(50, .1)
In other words, it's the second answer choice
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Explanation:
We have n = 50 people in the sample and p = 0.10 is the decimal form of 10%, to represent the probability of success. In this case, we define "success" as "the person passes the fitness test".
The random variable x is the count of how many people pass. So we could have x = 0, x = 1, x = 2, ..., x = 49, x = 50. Basically any whole number from 0 to 50 inclusive. Furthermore, x is approximately modeled by the binomial distribution which we denote as B(n, p) = B(50, 0.1)
So X ~ B(50, 0.1)
Answer: https://api-project-1022638073839.appspot.com/questions/how-do-you-use-the-sum-or-difference-identity-to-find-the-exact-value-of-sin-255#582997
Step-by-step explanation:
this will help you.
2.50 x 4 = 10
20 - 10 = 10
so his change would be $10
Step One
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Find the length of FO (see below)
All of the triangles are equilateral triangles. Label the center as O
FO = FE = sqrt(5) + sqrt(2)
Step Two
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Drop a perpendicular bisector from O to the midpoint of FE. Label the midpoint as J. Find OJ
Sure the Pythagorean Theorem. Remember that OJ is a perpendicular bisector.
FO^2 = FJ^2 + OJ^2
FO = sqrt(5) + sqrt(2)
FJ = 1/2 [(sqrt(5) + sqrt(2)] \
OJ = ??
[Sqrt(5) + sqrt(2)]^2 = [1/2(sqrt(5) + sqrt(2) ] ^2 + OJ^2
5 + 2 + 2*sqrt(10) = [1/4 (5 + 2 + 2*sqrt(10) + OJ^2
7 + 2sqrt(10) = 1/4 (7 + 2sqrt(10)) + OJ^2 Multiply through by 4
28 + 8* sqrt(10) = 7 + 2sqrt(10) + 4 OJ^2 Subtract 7 + 2sqrt From both sides
21 + 6 sqrt(10) = 4OJ^2 Divide both sides by 4
21/4 + 6/4* sqrt(10) = OJ^2
21/4 + 3/2 * sqrt(10) = OJ^2 Take the square root of both sides.
sqrt OJ^2 = sqrt(21/4 + 3/2 sqrt(10) )
OJ = sqrt(21/4 + 3/2 sqrt(10) )
Step three
find h
h = 2 * OJ
h = 2* sqrt(21/4 + 3/2 sqrt(10) ) <<<<<< answer.
X>-1/3, the graph would be filled everything to the right of -1/3 on the x axis
