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eduard
3 years ago
11

A bird releases waste from a height of

Mathematics
1 answer:
shepuryov [24]3 years ago
7 0

Answer:

5secs

Step-by-step explanation:

Given the equation of the height expressed ad;

h(t) = - 16t^2 + initial height

Given that initial height = 400feet

h(t) = - 16t^2 + 400

The waste will hit the ground at when h(t) = 0

substitute

0 =  - 16t^2 + 400

16t^2 = 400

t² = 400/16

t² = 25

t = √25

t = 5secs

Hence it will take the easte 5secs to hit the ground

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A charity fair raised $6,000 by selling 500 lottery tickets. There were two types of lottery tickets: A tickets cost $10 each, a
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<span>So the equations are 10A + 60B = 6000 and A + B = 500 

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5 0
3 years ago
Read 2 more answers
Assume that the heights of men are normally distributed with a mean of "71.3" inches and a standard deviation of 2.1 inches. If
Elza [17]

Answer:

0.0021 = 0.21% probability that they have a mean height greater than 72.3 inches.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Assume that the heights of men are normally distributed with a mean of "71.3" inches and a standard deviation of 2.1 inches.

This means that \mu = 71.3, \sigma = 2.1

Sample of 36:

This means that n = 36, s = \frac{2.1}{\sqrt{36}} = 0.35

Find the probability that they have a mean height greater than 72.3 inches.

This is 1 subtracted by the pvalue of Z when X = 72.3. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{72.3 - 71.3}{0.35}

Z = 2.86

Z = 2.86 has a pvalue of 0.9979

1 - 0.9979 = 0.0021

0.0021 = 0.21% probability that they have a mean height greater than 72.3 inches.

7 0
3 years ago
Can any one help me answer this Math question ?
kati45 [8]
The answer is 4*\sqrt(2), or 5.7 if rounded to the nearest tenth digit. Notice that this is a right triangle (F is the right angle). The length of FG and FE are both 4 units on the diagram. Therefore, according to the Pythagorean theorem, the length of EG is \sqrt(4^2+4^2)=4*\sqrt(2), which is about 5.7.
3 0
4 years ago
State whether the data described below are discrete or​continuous, and explain why.The heights (in feet) of different buildingsC
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Answer:  

Option D) The data are continuous because the data can take on any value in an interval

Step-by-step explanation:

We are given the following in the question:

Data: The heights (in feet) of different buildings

Discrete and continuous data:

  • Discrete data is the data that cannot take values in decimals and continuous data can take values in decimals.
  • Continuous data can take any value within an interval.
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  • Discrete data is counted where as continuous data is measured.

Thus, height is a continuous data since it can take any values within an interval and is measured.

Thus, the correct answer is

Option D) The data are continuous because the data can take on any value in an interval

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4 years ago
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Pavel [41]

Answer:

48/b

Step-by-step explanation:

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7 0
3 years ago
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