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kumpel [21]
3 years ago
12

Tickets to a play cost $4 in advance and $5 at the door. The theater club president wants to raise at least $400 from the ticket

sales. If the club sells 40 tickets in advance, what is the least number of tickets the club needs to sell at the door to reach the president’s goal?
Least number of tickets =
Mathematics
1 answer:
tresset_1 [31]3 years ago
6 0

Answer:

x≥48

Step-by-step explanation:

4×40 = 160

400-160 = 240

240÷5 = 48

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Answer:

Answer C is correct.

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