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3 years ago

What else would need to be congruent to show that ABC = DEF by SAS?

Mathematics

2 answers:

Vlad1618 [11]3 years ago

8 0

Answer:

A. $\overline{AC}\cong \overline{DF}$ .

Step-by-step explanation:

We have been given image of two triangles ABC and DEF. We are asked to find the information that will show that both triangles are congruent by SAS.

We know that two triangles are congruent by Side-Angle-Side congruence, if two sides and included angle of a triangle is equal to two sides and included angle of the other triangle.

We can see that angle A is included angle of side AB and AC, while angle D is included angle of side DE and DF.

We have been given that angle A is congruent to angle D and side AB is congruent to side DE.

To be both triangles congruent by SAS congruence, side AC must be congruent to side DF, therefore, option A is the correct choice.

Alona [7]3 years ago

3 0

The answer us A.

Line AC needs to be congruent to DF because for SAS (side angle side) we have a side (BA and DE) and an angle (A and D) so we need another side.

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Divide the following polynomials (a4 + 4b4) ÷ (a2 - 2ab + 2b2)

telo118 [61]

(a^4 + 4b^4) ÷ (a^2 - 2ab + 2b^2)
= [(a^2 - 2ab + 2b^2) (a^2 + 2ab + 2b^2)] / (a^2 - 2ab + 2b^2)
= a^2+2ab+2b^2 =The answer

(a + b)^2 = a^2 + 2ab + b^2 => square of sums
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and of course one of most important ones:
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Best Answer: (a^4 + 4b^4) ÷ (a^2 - 2ab + 2b^2)
= [(a^2 - 2ab + 2b^2) (a^2 + 2ab + 2b^2)] / (a^2 - 2ab + 2b^2)
= a^2 + 2ab + 2b^2
a^4 + 4b^4 => i.e. 4a^2b^2 ,
a^4 + 4a^2b^2 + 4b^4 => a^2 + 2ab + b^2 = (a + b)^2, if : a = a^2 , b = 2b^2:
(a^2 + 2b^2)^2 = a^4 + 4a^2b^2 + 4b^4 => We can't add or subtract the value to the expression.
a^4 + 4a^2b^2 + 4b^4 - 4a^2b^2 =>
(a^2 + 2b^2)^2 - 4a^2b^2 =>
(a^2 + 2b^2 - 2ab)(a^2 + 2b^2 + 2ab) =>
(a^2 - 2ab + 2b^2) (a^2 + 2ab + 2b^2)

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