Answer:
35.9 grams
Step-by-step explanation:
We use the formula:

Where
q is heat released
m is mass
C_p is the constant 2.44
ΔT is change in temperature
We put the info in the formula and solve for m (mass):

The mass of ethanol is 35.9 grams
Answer:
84 in²
Step-by-step explanation:
The side lengths of the triangle are 3 consecutive integers whose sum (the perimeter) is 42. The average of those integers, 42/3 = 14, is the middle of the three, so they are 13, 14, 15. We're told the perimeter is in inches, so all of these dimensions are inches.
These are the last three of 4 consecutive integers, so the first, the height of the triangle, is 12. The base of the triangle is the 3rd of the four integers, so is 14. Then the area is ...
A = (1/2)bh = (1/2)(14)(12) = 84 . . . . . square inches.
Answer:
IMPOSSIBLE
Step-by-step explanation:
First we set the equation system:

Now we set the matrix in order to have a solution for the system:
![\left[\begin{array}{ccc}1&1&0\\0&4&1\\4a&b&c\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%261%260%5C%5C0%264%261%5C%5C4a%26b%26c%5Cend%7Barray%7D%5Cright%5D)
Now we are going to apply Gauss-Jordan to find the solution of the system in terms of a, b and c:
![-4aR_{1}+R_{3}\rightarrow R_{3}\\\\{\left[\begin{array}{ccc}1&1&0\\0&4&1\\0&(-4a+b)&c\end{array}\right]](https://tex.z-dn.net/?f=-4aR_%7B1%7D%2BR_%7B3%7D%5Crightarrow%20R_%7B3%7D%5C%5C%5C%5C%7B%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%261%260%5C%5C0%264%261%5C%5C0%26%28-4a%2Bb%29%26c%5Cend%7Barray%7D%5Cright%5D)
Next step:
![(4a-b)R_{2}+4R_{3} \rightarrow R_{3}\\\\{\left[\begin{array}{ccc}1&1&0\\0&4&1\\0&0&(4a-b+c)\end{array}\right]](https://tex.z-dn.net/?f=%284a-b%29R_%7B2%7D%2B4R_%7B3%7D%20%5Crightarrow%20R_%7B3%7D%5C%5C%5C%5C%7B%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%261%260%5C%5C0%264%261%5C%5C0%260%26%284a-b%2Bc%29%5Cend%7Barray%7D%5Cright%5D)
Next step:
![(4a-b+c)R_{2}-R_{3} \rightarrow R_{2}\\\\{\left[\begin{array}{ccc}1&1&0\\0&4(4a-b+c)&0\\0&0&(4a-b+c)\end{array}\right]](https://tex.z-dn.net/?f=%284a-b%2Bc%29R_%7B2%7D-R_%7B3%7D%20%5Crightarrow%20R_%7B2%7D%5C%5C%5C%5C%7B%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%261%260%5C%5C0%264%284a-b%2Bc%29%260%5C%5C0%260%26%284a-b%2Bc%29%5Cend%7Barray%7D%5Cright%5D)
Next step:
![4(4a-b+c)R_{1}-R_{2} \rightarrow R_{1}\\\\{\left[\begin{array}{ccc}4(4a-b+c)&0&0\\0&4(4a-b+c)&0\\0&0&(4a-b+c)\end{array}\right]](https://tex.z-dn.net/?f=4%284a-b%2Bc%29R_%7B1%7D-R_%7B2%7D%20%5Crightarrow%20R_%7B1%7D%5C%5C%5C%5C%7B%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%284a-b%2Bc%29%260%260%5C%5C0%264%284a-b%2Bc%29%260%5C%5C0%260%26%284a-b%2Bc%29%5Cend%7Barray%7D%5Cright%5D)
With this solution, we have a new equation system:

This system can be solved by Cramer's rule, by finding the matrix determinant:
![\left[\begin{array}{ccc}16&-4&4\\16&-4&4\\4&-1&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D16%26-4%264%5C%5C16%26-4%264%5C%5C4%26-1%261%5Cend%7Barray%7D%5Cright%5D)

As the determinant is zero, we can say that the second system is imposible to solve.
Answer:
<em>" Expected Payoff " ⇒ $ 1.80 ; Type in 1.80</em>
Step-by-step explanation:
Take the probability of winning into consideration;

<em>Solution ; " Expected Payoff " ⇒ $ 1.80</em>
Answer:
8a + 32
Step-by-step explanation:
To use the distributive property, multiply 8 x a and multiply 8 x 4