a quantity of ethanol is cooled from 47.9° C to 12.3°C and releases 3.12 KJ of heat. what is the mass of the ethanol sample?
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Answer:
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Student B is wrong , student A is correct in simplifying the expression .
Expression B must be simplified to cot θ .
Formulas to be used are :
1 - θ =
θ
1 - θ =
θ .
Since , location of error is step 3 , we will start from there
[ ( 1 - θ ) / sin θ ] / cos θ = [ ( 1 -
θ ) / sin θ ] * [ 1 / cos θ ]
= ( 1 - θ ) / ( sin θ * cos θ )
= θ / ( sin θ * cos θ )
= cot θ .
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Since , the question is incomplete we assume it to be :
