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WARRIOR [948]
3 years ago
7

If you get it right I’ll give brainliest!

Mathematics
1 answer:
kifflom [539]3 years ago
3 0

Answer:

Vertical

Step-by-step explanation:

We can see that the line is parallel to the y-axis. This is an indicator that the line is vertical.

On the other hand, if the line was parallel to the x=axis, it would indicate that it is horizontal.

I hope this helps!

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Why might you want to round to the nearest hundred rather than the nearest ten?
Eva8 [605]
Rounding to the nearest hundredth would equal a more accurate and precise answer since more decimals are present. Your answer would be even more accurate if you rounded to the nearest thousandth.
7 0
3 years ago
Need help on this please
stellarik [79]
The answer to that question is 15.51
4 0
3 years ago
Read 2 more answers
Use the given data to find a regression line that best fits the price-demand data for price p in dollars as a function of the de
Rufina [12.5K]

Answer:

m=-\frac{7600}{8250}=-0.921

Nowe we can find the means for x and y like this:

\bar x= \frac{\sum x_i}{n}=\frac{550}{10}=55

\bar y= \frac{\sum y_i}{n}=\frac{1042}{10}=104.2

And we can find the intercept using this:

b=\bar y -m \bar x=104.2-(-0.921*55)=104.707

So the line would be given by:

y=-0.921 x +104.707

Step-by-step explanation:

For this case we have the following data given:

Demand (x): 10,20,30,40,50,60,70,80,90,100

Price (y): 141 , 133,126, 128,113,97, 90, 82,79,53

We want to construct a linear model like this:

y = mx +b

For this case we need to calculate the slope with the following formula:

m=\frac{S_{xy}}{S_{xx}}

Where:

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}

So we can find the sums like this:

\sum_{i=1}^n x_i =550

\sum_{i=1}^n y_i =1042

\sum_{i=1}^n x^2_i =38500

\sum_{i=1}^n y^2_i =115882

\sum_{i=1}^n x_i y_i =49710

With these we can find the sums:

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}=38500-\frac{550^2}{10}=8250

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}=49710-\frac{550*1042}{10}=-7600

And the slope would be:

m=-\frac{7600}{8250}=-0.921

Nowe we can find the means for x and y like this:

\bar x= \frac{\sum x_i}{n}=\frac{550}{10}=55

\bar y= \frac{\sum y_i}{n}=\frac{1042}{10}=104.2

And we can find the intercept using this:

b=\bar y -m \bar x=104.2-(-0.921*55)=104.707

So the line would be given by:

p(x)=-0.921 x +104.707

4 0
3 years ago
Help please are fractions help!!!!! thanks
Brrunno [24]

Answer:

See below

Step-by-step explanation:

To solve a proportion ( an equation with two equal fractions), cross multiply by  multiplying numerator and denominator of each fraction.

8/5=24/h                               8h = 5*24                    8h = 120              h=15

h/8=24/5                               5h = 8*24                    5h = 120              h= 24

h/5=24/8                               8h =5*24                     8h = 120              h=15

8/5=h/24                               5h = 8*24                    5h = 120              h=24

8/24=5/h                               8h = 24*5                    8h = 120              h = 15

5/8=h/24                               8h = 5*24                    8h =120               h = 15

h/5=8/24                             24h =5*8                      24h = 40             h = 5/3

3 0
4 years ago
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-Dominant- [34]

To begin, Arnold should sort on whether or not it is a screw, nut, bolt.

This might only be # 1 and 3 but you should be able to put together a number line with the information I provided. Some of the #s may look different but that is because I used the Least Common Denominator. Hope this helps!

Screws: Least to greatest (top = least)

4 Screws 4/64” x 3” long

12 Screws 5/64” x 3” long

3 Screws 6/64” x 4” long

6 Screws 11/64” x 4” long

16 Screws 24/64” x 2” long

1 Screw 28/64” x 3” long

1 Screw 32/64” x 3” long  

1 Screw 48/64” x 2” long

Hex Bolts: Least to greatest by diameter (top = least)

4 Hex bolts 1.5” x 4” long

4 Hex bolts 1.875” x 4” long

1 Hex bolt 2.25” x 2” long

6 Hex bolts 3.375” x 3” long

4 Hex bolts 3.75” x 3” long

3 0
3 years ago
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