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3 years ago

HELP PLEASE 15 POINTS

Mathematics

1 answer:

Crazy boy [7]3 years ago

7 0

Here is the answer

So as the triangle is congruent their sides angle all are same so the remaining angle in figure 2 (angle P) is 70

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How would I turn 0.46 into a fraction

Pepsi [2]

Step 1: 0.46 = 46⁄100
Step 2: Simplify 46⁄100 = 23⁄50 hope this helped u

6 0

3 years ago

Read 2 more answers

In ΔVWX, the measure of ∠X=90°, WX = 8.3 feet, and XV = 2.5 feet. Find the measure of ∠W to the nearest tenth of a degree.

kiruha [24]

Answer:

16.76°

Step-by-step explanation:

In ΔVWX, the measure of ∠X=90°, WX = 8.3 feet, and XV = 2.5 feet.

We want to find the measure of <W.

We know side length that is adjacent and opposite to <W.

We can use the tangent ratio, to find the measure of <W.

The tangent ratio is opposite over hypotenuse.

$\tan(m \angle \: w) = \frac{2.5}{8.3}$

$\tan(m \angle \: w) = 0.301$

Take tangent inverse to get:

$m \angle \: w= { \tan}^{ - 1} (0.301)$

$m \angle \: w=16.76 \degree$

7 0

3 years ago

If the length of a diagonal of a square is a, what is the length of its side?

balandron [24]

problem decoded dude

thank and follow me :)

3 0

3 years ago

Use the Newton-Raphson method to find the root of the equation f(x) = In(3x) + 5x2, using an initial guess of x = 0.5 and a stop

xxMikexx [17]

Answer with explanation:

The equation which we have to solve by Newton-Raphson Method is,

f(x)=log (3 x) +5 x²

$f'(x)=\frac{1}{3x}+10 x$

Initial Guess =0.5

Formula to find Iteration by Newton-Raphson method

$x_{n+1}=x_{n}-\frac{f(x_{n})}{f'(x_{n})}\\\\x_{1}=x_{0}-\frac{f(x_{0})}{f'(x_{0})}\\\\ x_{1}=0.5-\frac{\log(1.5)+1.25}{\frac{1}{1.5}+10 \times 0.5}\\\\x_{1}=0.5- \frac{0.1760+1.25}{0.67+5}\\\\x_{1}=0.5-\frac{1.426}{5.67}\\\\x_{1}=0.5-0.25149\\\\x_{1}=0.248$

$x_{2}=0.248-\frac{\log(0.744)+0.30752}{\frac{1}{0.744}+10 \times 0.248}\\\\x_{2}=0.248- \frac{-0.128+0.30752}{1.35+2.48}\\\\x_{2}=0.248-\frac{0.17952}{3.83}\\\\x_{2}=0.248-0.0468\\\\x_{2}=0.2012$

$x_{3}=0.2012-\frac{\log(0.6036)+0.2024072}{\frac{1}{0.6036}+10 \times 0.2012}\\\\x_{3}=0.2012- \frac{-0.2192+0.2025}{1.6567+2.012}\\\\x_{3}=0.2012-\frac{-0.0167}{3.6687}\\\\x_{3}=0.2012+0.0045\\\\x_{3}=0.2057$

$x_{4}=0.2057-\frac{\log(0.6171)+0.21156}{\frac{1}{0.6171}+10 \times 0.2057}\\\\x_{4}=0.2057- \frac{-0.2096+0.21156}{1.6204+2.057}\\\\x_{4}=0.2057-\frac{0.0019}{3.6774}\\\\x_{4}=0.2057-0.0005\\\\x_{4}=0.2052$