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Anuta_ua [19.1K]
3 years ago
7

Please answer the picture

Mathematics
1 answer:
Fiesta28 [93]3 years ago
6 0
12x^2 = 4/3
x^2 = 1/9
x= +/- 1/3 
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What is the equation of the line passing through the points (3,6) and (2,10)
andrezito [222]

Answer: y= - 4x+18

Step-by-step explanation:

Equation: y=mx+b

***remember: b is the y-intercept and m is the slope.

m=\frac{y2-y1}{x2-x1}

3= x1

2= x2

6= y1

10=y2

m=\frac{10-6}{2-3}= \frac{4}{1}= -4

m=-4

Now we have y=-4x+b , so let's find b.

You can use either (x,y) such as (3,6) or (2,10) point you want..the answer will be the same:

   (3,6). y=mx+b or 6=-4 × 3+b, or solving for b: b=6-(-4)(3). b=18.

   (2,10). y=mx+b or 10=-4 × 2+b, or solving for b: b=10-(-4)(2). b=18.

Equation of the line: y=-4x+18

3 0
3 years ago
Drag the labels to the correct locations on the table. Each label can be used more than once.
Julli [10]

Answer:

first one linear

second one quadratic

linear

Step-by-step explanation:

6 0
3 years ago
What is the solution for <br> -8(8x-4)+10(-7x-6)
77julia77 [94]
<span>-8(8x-4)+10(-7x-6) 
=-64x + 32 - 70x - 60
= -134x -28

hope it helps</span>
5 0
2 years ago
Anybody know the correct answer?
earnstyle [38]

Since \csc^2{x}=\frac{1}{\sin^2{x}} and \cot^2{x}=\frac{\cos^2{x}}{\sin^2{x}}, we can rewrite the right side of the equation as

\frac{1}{\sin^2{x}}-\frac{\cos^2{x}}{\sin^2{x}} =\frac{1-\cos^2{x}}{\sin^2{x}}

Using the identity \sin^2{x}+\cos^2{x}=1, we can subtract \cos^2{x} from either side to obtain the identity \sin^2{x}=1-\cos^2{x}

substituting that into our previous expression, the right side of our equation simply becomes

\frac{\sin^2{x}}{\sin^2{x}}=1

We can now write our whole equation as

3\tan^2{x}-2=1

Adding 2 to both sides:

3\tan^2{x}=3

dividing both sides by 3:

\tan^2{x}=1

\tan{x}=\pm1

When 0 ≤ x ≤ π, tan x can only be equal to 1 when sin x = cos x, which happens at x = π/4, and it can only be equal to -1 when -sin x = cos x, which happens at x = 3π/4

4 0
3 years ago
If sin theta = 3/5 and cos theta=4/5 what is tan theta
kolbaska11 [484]
Tan is sin over cos do tan they = (3/5)/(4/5) = 3/4
5 0
3 years ago
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