Question

If f(x)=2x+1 and g(x)=(x^2)-7, find (f/g)(x).

Answer 1

$f(x)=2x+1;\ g(x)=x^2-7\\\\\left(\dfrac{f}{g}\right)(x)=\dfrac{f(x)}{g(x)}\\\\\boxed{\left(\dfrac{f}{g}\right)(x)=\dfrac{2x+1}{x^2-7}}$

Answer 2

Answer:

Value of (f/g)(x) is:

$\dfrac{2x+1}{x^2-7}$

Step-by-step explanation:

f(x)=2x+1 and g(x)=x²-7

$(\dfrac{f}{g})(x)=\dfrac{f(x)}{g(x)}$

⇒$(\dfrac{f}{g})(x)=\dfrac{2x+1}{x^2-7}$

Hence, value of (f/g)(x) is:

$\dfrac{2x+1}{x^2-7}$