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Nastasia [14]
3 years ago
5

If f(x)=2x+1 and g(x)=(x^2)-7, find (f/g)(x).

Mathematics
2 answers:
alexdok [17]3 years ago
6 0

f(x)=2x+1;\ g(x)=x^2-7\\\\\left(\dfrac{f}{g}\right)(x)=\dfrac{f(x)}{g(x)}\\\\\boxed{\left(\dfrac{f}{g}\right)(x)=\dfrac{2x+1}{x^2-7}}

san4es73 [151]3 years ago
6 0

Answer:

Value of (f/g)(x) is:

\dfrac{2x+1}{x^2-7}

Step-by-step explanation:

f(x)=2x+1 and g(x)=x²-7

(\dfrac{f}{g})(x)=\dfrac{f(x)}{g(x)}

⇒(\dfrac{f}{g})(x)=\dfrac{2x+1}{x^2-7}

Hence, value of (f/g)(x) is:

\dfrac{2x+1}{x^2-7}

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