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Talja [164]
3 years ago
14

Two students solved a problem. One student solved it correctly and one student solved it incorrectly. Determine which student so

lved the problem correctly.
The problem: 53+42
5
3
+
4
2

Tom: 5+5+5×4+4=120
5
+
5
+
5
×
4
+
4
=
120

Maggie: 5×5×5+4×4=141
Mathematics
1 answer:
eduard3 years ago
3 0

Answer:

Maggie

Step-by-step explanation:

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What is the range of the function y=3√x+8?<br> O-∞ O-8 O 0≤y&lt;∞<br> O 2≤y&lt;∞
Ket [755]

Answer: 0 ≤ y < ∞

Step-by-step explanation:

   First, let us graph the function. See attached.

-><em> If I graphed the formatting of the square root sign incorrectly, please let me know so I can fix the answer.</em>

<em />

  The range of the function is all of the function's output values. In this case, all of the y values.

        0 ≤ y < ∞

5 0
2 years ago
2/3 of a pizza was left over. A group of friends divided the leftover pizza into pieces each
e-lub [12.9K]

Answer:

We can't directly answer it without the number of friends, so it would need to be a variable.

A=number of friends. X= slices

2/3 ÷ a = x

6 0
3 years ago
PLEASE HELP!<br> subtract 2 from the sum of j and 5
Anna [14]

Answer:

(j+5)-2 That's the answer

5 0
3 years ago
Read 2 more answers
Please help. and please explain the process too
denis-greek [22]
The polynomial as per the given of the problem is f(x)=3x²-21x+30
Find the roots of this polynomial:
 x₁=[-b+√b²-4ac)]/2a and x₂ =[-b-√b²-4ac)]/2a
Plug in : x₁ = [21+√(21²-4(3)(30)]/6 = [21+√81}/6 ; x₁ = 5
and x₂ = [21-√(21²-4(3)(30)]/6 = [21-√81]/6 ; x₂ = 2
 Remark: I don't understand where did you bring √5 , it should be 5
6 0
4 years ago
Given:• PQRS is a rectangle.• mZ1 = 50°Р21SRWhat is mZ2?130°85°70°65°
Over [174]

To answer this question, we need to recall that: "the diagonals of a rectangle bisect each other"

Thus, if we assign the point of intersection of the two diagonals in the rectangle as point O, we can say that the triangle OQR is an "isosceles triangle". Note that this is because the lengths OR and OQ are equal since we know that: "the diagonals of a rectangle bisect each other". See the below diagram for clarity.

Now, we have to recall that:

- the base angles of any isosceles triangle are equal. This is a fact, and this means that the angles

- also the sum of all the angles in any triangle is 180 degrees

Now, considering the isosceles triangle OQR, we have that:

\angle OQR+\angle ORQ+\angle ROQ=180^o

Now, since the figure already shows that angle m\angle2+\angle ORQ+50^o=180^oNow, since we have established that the base angles m\angle2+m\angle2+50^o=180^owe can now solve the above equation for m<2 as follows:

\begin{gathered} m\angle2+m\angle2+50^o=180^o \\ \Rightarrow2m\angle2+50^o=180^o \\ \Rightarrow2m\angle2=180^o-50^o \\ \Rightarrow2m\angle2=130^o \\ \Rightarrow m\angle2=\frac{130^o}{2}=65^o \end{gathered}

Therefore, the correct answer is: option D

7 0
1 year ago
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