One system of equations would be
L = w+4
H = w-10
4H + 8(wL) = 1544
There is one viable solution; the width is 12, the length is 16, and the height is 2.
Using substitution with the system of equations, we have
4(w-10)+8(w(w+4))=1544
4w-40+8(w²+4w)=1544
4w-40+8w²+32w=1544
Combining like terms, we have
8w²+36w-40=1544
Factoring out a 4, we have
4(2w²+9w-10)=1544
Dividing both sides by 4 gives us
2w²+9w-10=386
Subtract 386 from both sides to get
2w²+9w-396=0
Using the quadratic formula, we have

Since a negative width makes no sense, we know that w=12.
This means L=w+4=12+4=16 and H=w-10=12-10=2
Answer:
I)One to three roots.
ii)Two or zero extrema.
iii)One inflection point.
iv)Point symmetry about the inflection point.
v)Range is the set of real numbers.
vi)Three fundamental shapes.
vii)Four points or pieces of information are required to define a cubic polynomial function.
Roots are solvable by radicals.
You can not divide by zero in math.
Answer:
Both
Step-by-step explanation:
Both because they are each a pund plz rate 5
for every completed length of audiobook, Zhen spends 6.5 hours working.
C.Zhen spends 6 1/2 hours working per audiobook