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Nikolay [14]
3 years ago
7

(-9,-13) , [7 1/2, 3 1/2], (5,1), (4,0), (0,__) what is the next number?

Mathematics
1 answer:
jok3333 [9.3K]3 years ago
5 0

Answer:

56

Step-by-step explanation:

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Which of the following is the correct
vekshin1

Answer:

which of what? no answer choices.

3 0
3 years ago
What is the volume of a cone with diameter 21 m and height 4 m?
natima [27]

For this case we have by definition, that the volume of a cone is given by:

V = \frac {1} {3} * \pi * r ^ 2 * h

Where:

A: It is the cone radius

h: It's the height

They tell us that the diameter is 21 m, then the radius is half the diameter, that is: 10.5m. The height is 4m. Substituting the data:

V = \frac {1} {3} * \pi * (10.5) ^ 2 * 4\\V = \frac {1} {3} * \pi * 110.25 * 4\\V = 147 \pi.

Finally, the volume of the cube is147 \pi \ m ^ 3

ANswer:

Option B

3 0
3 years ago
DUE BEFORE 5:OO!!!!!!
AleksAgata [21]
X + y = 6
x - 6y = -9

Subtract the equations, you get:

y - (-6y) = 6 - (-9)
7y = 15

y = 15/7

x + 15/7 = 6
x + 15/7 = 42/7
x = (42-15)/7
x = 27/15

None of your answer choices are correct, since the solution to the systems of equation is (27/15, 15/7)
6 0
3 years ago
1. (a) Use the integral test to show that P[infinity] n=1 1/n4 converges. (b) Find the 10th partial sum, s10, of the series P[in
scZoUnD [109]

Answer:

Step-by-step explanation:

a) \int\limits^{\infty} _1 {\frac{1}{n^4} } \, dn\\ =\frac{n^{-3} }{-3}

Substitute limits to get

= \frac{1}{3}

Thus converges.

b) 10th partial sum =

\int\limits^{10} _1 {\frac{1}{n^4} } \, dn\\ =\frac{n^{-3} }{-3}

=\frac{-1}{3} (0.001-1)\\= 0.333

c) Z [infinity] n+1 1 /x ^4 dx ≤ s − sn ≤ Z [infinity] n 1 /x^ 4 dx, (1)

where s is the sum of P[infinity] n=1 1/n4 and sn is the nth partial sum of P[infinity] n=1 1/n4 .

(question is not clear)

3 0
3 years ago
Find the area of the figure. Round to the nearest tenth if necessary.
r-ruslan [8.4K]
Area =  area of rectangle - area of 2 hemispheres
         = 24 * 32 - pi * 12^2
         = 315.6  sq units
5 0
3 years ago
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