Which phrase describes density? height of a point above sea level force pushing on an area or a surface amount of mass in a cert
2 answers:
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Answer:
% change in stopping distance = 7.34 %
Step-by-step explanation:
The stooping distance is given by
We will approximate this distance using the relation
dx = 26 - 25 = 1
T' = 2.5 + x
Therefore
This is the stopping distance at x = 25
Put x = 25 in above equation
2.5 × (25) + 0.5× + 2.5 + 25 = 402.5 ft
Stopping distance at x = 25
T(25) = 2.5 × (25) + 0.5 ×
T(25) = 375 ft
Therefore approximate change in stopping distance = 402.5 - 375 = 27.5 ft
% change in stopping distance = × 100
% change in stopping distance = 7.34 %
Hello.
We are solving -9.4 > 1.7x + 4.2.
First we need to swap sides:
Now we need to subtract 4.2 from both sides.
1.7x + 4.2 = -9.4
-4.2 . -4.2
Now let's combine -4.2 + 4.2 which is 0.
We get 1.7x < -9.4 - 4.2
Now let's divide both sides by 1.7
1.7x | -13.6
1.7 1.7
x < -13.6
1.7
So we just divided to get x < -8.