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4vir4ik [10]
4 years ago
10

In a horticultural experiment, 200 seeds were planted in plot i and 300 were planted in plot ii. if 57 percent of the seeds in p

lot i germinated and 42 percent of the seeds in plot ii germinated, what percent of the total number of planted seeds germinated?
Mathematics
1 answer:
Sonja [21]4 years ago
6 0
Plot i = 200 seeds
Geminated = 57% of 200 = 0.57 x 200 = 114 seeds

Plot ii = 300 seeds
Geminated = 42% of 300 = 0.42 x 300 = 126 seeds

Total geminated seeds = 114 + 126 = 240 
Total seeds = 200 + 300 = 500

Percentage = 240 ÷ 500 x 100 = 48%
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Answer:

The solution for k is the interval (-3.5,1.5)

Step-by-step explanation:

we have

k(x^{2}+1)=x^{2}+3x-3

kx^{2}+k=x^{2}+3x-3

x^{2}-kx^{2}+3x-3-k=0

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we know that

If the discriminant is greater than zero . then the quadratic equation has two real and distinct solutions

The discriminant is equal to

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In this problem we have

a=(1-k)

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c=-(3+k)

substitute

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so

21-8k-4k^{2} > 0

solve the quadratic equation by graphing

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see the attached figure

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3 years ago
The nth term = 1x2^n-1 find the 7th term
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Four friends are creating posters for their presentations, which will be delivered in different locations. Which person should c
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Step-by-step explanation:

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Lindsey, who is delivering her speech in a large auditorium

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If y varies directly as x, and y = 15 as x = -3, find y for the x-value of 4.
NeX [460]
Y = kx
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answer

<span>y = -20 when the x = 4.</span>


3 0
3 years ago
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