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goldfiish [28.3K]
2 years ago
15

Triple a number, x, increased by 1 is between -20 and 10. What are the solutions for x?

Mathematics
1 answer:
Bumek [7]2 years ago
3 0
Hello,
-20 \leq 3x+1 \leq 10\\
\Rightarrow\ -21 \leq 3x \leq 9\\
\Rightarrow\ -7 \leq x \leq 3\\

Sol=[-7\ 3]\ if\ x\ is\ a\ real.


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1 year ago
If \dfrac{x-1}{3}=k 3 x−1 ​ =kstart fraction, x, minus, 1, divided by, 3, end fraction, equals, k and k=3k=3k, equals, 3, what i
earnstyle [38]
For this case we have the following expression:
 (x-1) / (3) = k
 Substituting the value of k = 3 we have:
 (x-1) / (3) = 3
 From here, we must clear the value of x.
 We have then:
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7 0
3 years ago
QUICK!! 18x^2+21x-60=0 pls give me the steps as well
Anton [14]

Answer:

<h2>x1 =  -  \frac{5}{2}</h2>

x2 =  \frac{4}{3}

Step-by-step explanation:

18 {x}^{2}  + 21x - 60 = 0

Divide both sides of the equation by 3

6 {x}^{2}  + 7x - 20 = 0

Write 7x as a difference

6 {x}^{2}  + 15x - 8x - 20 = 0

Factor out 3x from the expression

3x(2x + 5) - 8x - 20 = 0

Factor out -4 from the expression

3x(2x + 5) - 4(2x + 5) = 0

Factor out 2x + 5 from the expression

(2x + 5)(3x - 4) = 0

When the product of factors equals 0 , at least one factor is 0

2x + 5 = 0

3x - 4 = 0

Solve the equation for X

2x + 5 = 0

Move constant to R.H.S and change its sign

2x = 0 - 5

Calculate the difference

2x  =  - 5

Divide both sides of the equation by 2

\frac{2x}{2}  =  \frac{ - 5}{2}

Calculate

x 1=  -  \frac{5}{2}

Again,

3x - 4 = 0

Move constant to RHS and change its sign

3x = 0 + 4

Calculate the sum

3x = 4

divide both sides of the equation by 3

\frac{3x}{3}  =  \frac{4}{3}

Calculate

x 2=  \frac{4}{3}

Hope this helps..

Best regards!!

5 0
3 years ago
Read 2 more answers
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