Answer:
Step-by-step explanation:
The aim of this question is to prove that the product of two rationals is rational.
<u>To proof:</u>
If
are arbitrary rational numbers.
Thus, going by the definition of rational, there exist integers
a, b, ≠ 0, c, and d ≠ 0 ; ![x = \dfrac{a}{b} \ and \ y = \dfrac{c}{d}](https://tex.z-dn.net/?f=x%20%3D%20%5Cdfrac%7Ba%7D%7Bb%7D%20%5C%20and%20%5C%20y%20%3D%20%5Cdfrac%7Bc%7D%7Bd%7D)
Hence, ![xy = (\dfrac{a}{b})(\dfrac{c}{d}) = \dfrac{ac}{bd}](https://tex.z-dn.net/?f=xy%20%3D%20%28%5Cdfrac%7Ba%7D%7Bb%7D%29%28%5Cdfrac%7Bc%7D%7Bd%7D%29%20%3D%20%5Cdfrac%7Bac%7D%7Bbd%7D)
Since a and c are integers, then e = ac appears to be an integer as well.
Also, provided that b and d are non-zero integers;
f =bd appears to be a non-zero integer.
Therefore,
, and going by the definition of rational, xy is rational.
Hence, from the complete question:
The order of the statement is:
7,6,3,5,2,4
The statements that should not be used in the proof are:
1 N
8 N
9 N
10 N
11 N