Answer:
Number of quarters → 15
Number of dimes → 2
Step-by-step explanation:
Let the number of dimes I have = y
And number of quarters = x
Since, I have amount in my pocket = $2
Therefore, 0.10y + 0.25x = 2
100(0.10y + 0.25x) = 100×2
25x + 10y = 200
5x + 2y = 40
2y = -5x + 40
y = -2.5x + 20 ---------(1)
Total number of coins in my pocket = 17
x + y = 17
y = -x + 17 ---------(2)
By using a graphing calculator we can graph these two lines (As attached)
Solution of the given system of equations will be the point of intersection of these lines.
Solution → (2, 15)
Number of quarters → 15
Number of dimes → 2
A.Calculate the mean,median and mode.(3 points each) 1.)1,2,3,4,5 2.)2,3,4,5,6,6 3.)6,7,5,4,5,6,2,5
zlopas [31]
Answer:
Step-by-step explanation:
1.)1,2,3,4,5
mean=sum of all values/number of values
=1+2+3+4+5/5
=15/5
mean=3
Mode :
In the given data, no observation occurs more than once.
Hence the mode of the observations does not exist, means mode=0.
Median
1,2,3,4,5
Middle value is 3 so the median is 3.
2.)2,3,4,5,6,6
mean=sum of all values/number of values
=2+3+4+5+6+6/6
=26/6
mean =4.33
Mode
is that value of the observation which occurs maximum number of times so here mode is 6.
Median
2,3,4,5,6,6
4+5/2
9/2
median=4.5
3.)6,7,5,4,5,6,2,5
mean=sum of all values/number of values
=6+7+5+4+5+6+2+5/8
=40/8
mean =5
Mode
is that value of the observation which occurs maximum number of times so here mode is 5
Median
2,4,5,5,5,6,6,7
5+5/2
10/2
median=5
Well, they are equivalent, but I'm not sure if that's exactly what you're asking. :)
Answer:
area: 25.12
circumference will always be 3.14
Step-by-step explanation:
Uh oH 6+ well I guess than 6+ if this get wrong then I'm sorry
