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Igoryamba
3 years ago
12

WhAt is the average ?3 4 5 10

Mathematics
1 answer:
Dima020 [189]3 years ago
8 0
Average =
2 + 7 + 19 + 24 + 25
——————————
5
=
77
—
5
= 15.4
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A large chocolate bar has a base area of 47.1 square feet and it’s length is 0.7 feet longer than twice it’s width. Find the len
VLD [36.1K]

Answer:

The dimensions of the bar are width = 4.68099 feet and length = 10.06198 feet

Step-by-step explanation:

A chocolate bar has a rectangular shape, therefore it's area is given by the following formula:

area = width*length

In this case the length is 0.7 feet longer than twice the width, therefore:

length = 2*width + 0.7

Applying the second equation on the first one and using the data from the question we have:

47.1 = width*(2*width + 0.7)

47.1 = 2*width² + 0.7*width

2*width² + 0.7*width = 47.1

width² + 0.35*width = 23.55

width = \frac{-0.35 \pm \sqrt{0.35^2 -4*1*(-23.55)}}{2*1} = -0.175 \pm 4,85599

width = 4.68099 or width = -5.03099

Since the width can't be negative, it can only be 4.68099 feet.

length = 2*4.68099 + 0.7 = 10.06198 feet.

6 0
3 years ago
What value of x is in the solution set of 4x – 12 ≤ 16 + 8x?
gtnhenbr [62]
The solution for the x-value in this set is -7≤x
4 0
3 years ago
Read 2 more answers
Could anyone help me on number 3?
xeze [42]

Answer:

n = 2m-4

Step-by-step explanation:

n+2/m-1=2

n+2=2(m-1)

n+2=2m-2

n=2m-2-2

n=2m-4

6 0
3 years ago
A wood frame costs $1.50. Use a property to write an equivalent expression for the cost of a wood frame.
podryga [215]
Let the width of the frame = x
Let the cost of a linear foot of the frame = y
Let the inside dimension of the length of the frame = a
Let the inside dimension of the width of the frame = b.

The total length of the frame = 2*a + 4x
The total width of the frame = 2b

The total amount of the frame in feet is (2a + 4x + 2b)*y = Cost
If this is incorrect please leave a message on my home page.
6 0
3 years ago
Help plz i need it :(
mr_godi [17]

Answer:

B.

C.

D.

E.

Step-by-step explanation:

6 0
3 years ago
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