Area of a square = Side × Side
Side = 7x-3
Area of the square = (7x-3) × (7x-3)
= 7x(7x-3) -3(7x-3)
= 49x^2 -21x -21x +9
=49x^2 -42x +9
If you’re finding the measure of its complement, the sum of both angles will always be 90*
x+38 = 90
-38 | -38
x = 52
the measure of its complement is 52*
Yes, you are right, if it approaches from the left, the limit is infinity and if it approaches from the right, the limit is negative infinity. The limit does not exist because it reaches infinity as x approaches pi/2 and the limits are the same when the value is approached from the opposite directions.
I'm assuming it would be the same shape? That's also assuming that it's referring to congruent shapes and angles.
No, its D
Just look at the rounds mentioned and subtract the scores from higher round with lower round.
Look at A: round 2 score - round 1 score = -2?
-3 -1 = -4 change, not -2 change so it is wrong
Look at B: round 3 score - round 1 score =-1?
-2-1 =-3 change, not -1 change so it is wrong
Look at C: round 3 score - round 2 score =-1?
-2 -(-3) = 1 change, not -1 change so it is wrong
Look at D: round 3 score - round 1 score =-3?
-2-1 = -3 change, matches with -3 so it is correct.
