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3 years ago

A photo processing place can develop 416 photos in 8 hours. How many photos can it develop every hour?

Mathematics

1 answer:

Rina8888 [55]3 years ago

5 0

Answer:

52 photos per hour

Step-by-step explanation:

8 goes into 400 50 times, and goes into the remaining 16 twice. Therefore, 416 photos/8 hour=52

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20 PTS PLEASE HELP ASAP!

gtnhenbr [62]

Answer:

Slope is 1/2

Step-by-step explanation:

Use the slope formula. Say S = the 1st point and T = the 2nd point.

m = 20 - 10 10 1

------------ = ----------- = ---

20 - 0 20 2

The equation for slope is also y = mx + b

m is the slope, b is the y-intercept.

Therefore, if you look at the 1st choice, you can see that 1/2 is in the place of m, meaning that 1/2 is the slope of line ST

I dunno how to do the other way

7 0

3 years ago

Find the arc length of the partial circle..

Gala2k [10]

Answer:

The arc length of the partial circle is $6\pi\ units$

Step-by-step explanation:

we know that

The circumference of a circle is equal to

$C=2\pi r$

In this problem we have a 3/4 of a circle

the circumference is equal to

$C=(\frac{3}{4})2\pi r$

$C=\frac{3}{2}\pi r$

we have

$r=4\ units$

substitute

$C=\frac{3}{2}\pi (4)$

$C=6\pi\ units$

5 0

4 years ago

(4+4)÷22×2<br><br> plss someone answer hurry <3

sineoko [7]

Answer:

first is 4+4=8.........second is 22×2=11 ..........third is 8÷11=0.7272727273 u can do it 0.72

Step-by-step explanation:

hope this help

7 0

3 years ago

Read 2 more answers

Suppose the average tread-life of a certain brand of tire is 42,000 miles and that this mileage follows the exponential probabil

Ahat [919]

Answer: The probability that a randomly selected tire will have a tread-life of less than 65,000 miles is 0.7872 .

Step-by-step explanation:

The cumulative distribution function for exponential distribution is :-

$P(X\leq x)=1-e^{\frac{-x}{\lambda}}$ , where $\lambda$ is the mean of the distribution.

As per given , we have

Average tread-life of a certain brand of tire : $\lambda=\text{42,000 miles }$

Now , the probability that a randomly selected tire will have a tread-life of less than 65,000 miles will be :

$P(X\leq 65000)=1-e^{\frac{-65000}{42000}}\\\\=1-e^{-1.54761}\\\\=1-0.212755853158\\\\=0.787244146842\approx0.7872$

Hence , the probability that a randomly selected tire will have a tread-life of less than 65,000 miles is 0.7872 .

8 0

4 years ago

And engineer in blueprint calls for a 10.5 foot clearance from some pipes to the wall the pipes are currently 8.25 feet from the

tatuchka [14]

Answer:222

Step-by-step explanation:

add it

7 0

3 years ago