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3 years ago

1. 1*1/6=___

Mathematics

1 answer:

Ratling [72]3 years ago

7 0

Step-by-step explanation:

1. 1*1/6= 1 /6=1.67

2. 9*7/10= 63/10= 6.3

3. 7*4/8= 28/8= 3.5

4. 1/2 of 2= 1/2*2= 0.5*2= 1

5. 1/12 of 2= 1/12*2= 8.33*2= 16.66

6.2/6 of 2= 2/6*2= 3.33*2= 6.66

7. 1/3 of 5= 1/3*5= 3.33*5= 16.65

8. 3/10 of 8= 3/10*8= 0.3*8= 2.4

Hope it's help you ♥️

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Answer:

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Step-by-step explanation:

The given expression is:

$\dfrac{1+\sqrt{2}}{2+\sqrt{3}}$

We have to simply it and express it in the form of:

$A(1+\sqrt{B})-(\sqrt{C}+\sqrt{D})$

Multiply and divide the given expression with $2-\sqrt 3$ :

$\dfrac{1+\sqrt{2}}{2+\sqrt{3}} \times \dfrac{2-\sqrt 3}{2-\sqrt 3}\\\Rightarrow \dfrac{(1+\sqrt{2}) \times (2-\sqrt 3)}{(2+\sqrt{3})\times (2-\sqrt 3)}\\\Rightarrow \dfrac{2+2\sqrt2-\sqrt3-\sqrt6}{2^2-(\sqrt{3})^2}\\\Rightarrow \dfrac{2+2\sqrt2-\sqrt3-\sqrt6}{4-3}\\\Rightarrow \dfrac{2(1+\sqrt2)-(\sqrt3+\sqrt6)}{1}\\\Rightarrow 2(1+\sqrt2)-(\sqrt3+\sqrt6)$

It is the simplified form of given expression.

Formula used:

$(a+b)(a-b) = a^{2} -b^{2}$

Comparing the simplified expression with $A(1+\sqrt{B})-(\sqrt{C}+\sqrt{D})$

$2(1+\sqrt2)-(\sqrt3+\sqrt6)=A(1+\sqrt{B})-(\sqrt{C}+\sqrt{D})\\\Rightarrow A =2, B=2, C=3\ and\ D=6$

So, value of

$A+B+C+D = 2+2+3+6 = 13$

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