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grigory [225]
3 years ago
13

Consider the following first line from a Java method definition.

Computers and Technology
1 answer:
PSYCHO15rus [73]3 years ago
8 0

Answer:

d.

Explanation:

The line of code that would legally overload the above method would be

public static boolean compute(float n, int x) {

This is because in order to legally overload a method the arguments that are passe

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Write a program that asks the user for three strings. Then, print out whether the first string concatenated to the second string
ipn [44]

Answer:

import java.util.Scanner;

public class num5 {

   public static void main(String[] args) {

       Scanner in = new Scanner(System.in);

       System.out.println("Enter The First String");

       String str1 = in.next();

       System.out.println("Enter The Second String");

       String str2 = in.next();

       System.out.println("Enter The Third String");

       String str3 = in.next();

       String oneAndTwo = str1+str2;

       if(str3.equals(oneAndTwo)){

           System.out.println(str1+" + "+str2+" is equal to "+str3+"!");

       }

       else

           System.out.println(str1+" + "+str2+" is not equal to "+str3+"!");

   }

}

Explanation:

  • Implemented in Using Java Programming Language
  • Import Scanner Class to prompt and receive users' input
  • Create three string variables and store the three values entered by the user (str1, str2 and str3)
  • Concatenate str1 and str2 using the + operator and assign to a new variable
  • Use the if statement with Java's .equals() method to check for equality of the new string with the third string
  • Print the appropriate message if the equal or not
8 0
3 years ago
a) (20 points) Define the method inDogish recursively such that it returns true if the word is in dog-ish and false if it is not
tia_tia [17]

Answer:

/ Main.java

class Main {

     public static void main(String[] args) {

           //System.out.println(inDogish("aplderogad"));

           //System.out.println(inXish("aplderogad", "dog"));

     }

     // returns true if the word is in dog-ish

     // returns false if word is not in dog-ish

     public static boolean inDogish(String word) {

           /**

           * Note: we can use the inXish() method to complete this method in a

           * single line if you want. just write 'return inXish(word,"dog");' and

           * you are done.

           */

           // if word is null or empty, returning false

           if (word == null || word.length() == 0) {

                 return false;

           }

           // converting word to lower case

           word = word.toLowerCase();

           // if 'd' does not exist on the word, returning false

           if (!dogishHelper(word, 'd')) {

                 return false;

           }

           // removing the characters upto first 'd' in word

           word = word.substring(word.indexOf('d') + 1);

           // if 'o' does not exist on the word, returning false

           if (!dogishHelper(word, 'o')) {

                 return false;

           }

           // removing the characters upto first 'o' in word

           word = word.substring(word.indexOf('o') + 1);

           // if 'g' does not exist on the word, returning false, otherwise

           // returning true

           if (!dogishHelper(word, 'g')) {

                 return false;

           } else {

                 return true;

           }

     }

     // necessary to implement inDogish recursively.

     // returns true if letter is in word, else not.

     public static boolean dogishHelper(String word, char letter) {

           // if word is empty, returning -1

           if (word == null || word.length() == 0) {

                 return false;

           }

           // if first character in word is letter, returning 0

           if (word.charAt(0) == letter) {

                 return true;

           }

           return dogishHelper(word.substring(1), letter);

     }

     // the best thing about the above helper method is that we can use it in

     // inXish method also

     // a generalized version of the inDogish method

     public static boolean inXish(String word, String x) {

           // if x is empty, returning true (base case, which means all the letters

           // in x are in word in that order)

           if (x.length() == 0) {

                 return true;

           }

           // getting first character of x

           char first = x.charAt(0);

           // if first character does not exist on the word, returning false

           if (!dogishHelper(word, first)) {

                 return false;

           }

           // calling and returning inXish recursively, passing the word after

           // removing characters upto first occurrance of char first, and x after

           // removing first character from it

           return inXish(word.substring(word.indexOf(first) + 1), x.substring(1));

     }

}

Explanation:

7 0
4 years ago
Definition of firewall
miv72 [106K]
A partition made of fireproof material to prevent the spread of a fire from one part of a building or ship to another or to isolate an engine compartment, as on a plane, automobile, etc.
3 0
2 years ago
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Aspire is a test you take to prepare for the<br> A. PSAT<br> B. SAT<br> C. ACT<br> D. FAFSA
just olya [345]

Answer:

ACT

Explanation:

"ACT Aspire is a powerful tool to help students and their parents monitor progress toward a successful ACT test from third grade through tenth grade. The Aspire test assess students' readiness in five areas covered by the ACT test: English, math, reading, science and writing." - https://greentestprep.com/resources/act-prep/act-aspire-test/

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3 years ago
Which of the following is not a requirement of a linear programming problem?
vampirchik [111]

requirements of a linear programming problem, moderate

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