Question

Graph a line that contains the point (3,-6) and has slope of -1/2​

Answer 1

Answer:

Step-by-step explanation:

Let the equation of the line is,

y = mx + b

Here, m = slope of the line

b = y intercept

Since, m = -$\frac{1}{2}$

Equation of the line will be,

y = $-\frac{1}{2}x+b$

Since, a point (3, -6) lies on the line,

-6 = $-\frac{3}{2}+b$

b = -6 + 1.5

b = -4.5

Equation of the line will be,

$y=-\frac{x}{2}-\frac{9}{2}$

Table for the points on the graph,

x      -4         -3         -2        -1          0        

y      -2.5      -3       -3.5      -4       -4.5    

Plot these points and join them to get the graph of a line.