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3 years ago

Complete the table for the given rule. Y= x+2/3

Mathematics

1 answer:

3241004551 [841]3 years ago

3 0

Answer:

decimal: x0.6 or fraction: 2/3

Step-by-step explanation:

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The oblique pyramid has a square base.

Brums [2.3K]

Good evening ,

______

Answer:

the volume of the pyramid = 5cm³

___________________

Step-by-step explanation:

the volume of the pyramid = (b×h)/3 = (2²×3,75)/3 = (4×3,75)/3 = 15/3 = 5.

6 0

3 years ago

What is the simplest form of the expression 2x(x â’ 6) â’ 7x2 â’ (13x â’ 3)? A. 5x2 â’ 25x 3 B. -5x2 â’ 25x 3 C. -5x2 x 3 D. -5x

kobusy [5.1K]

The simplest form of the given expression can be written as -5x² + 25x - 3.

The given parameters:

2x(x + 6) - 7x² + (13x - 3)

The given expression can be simplified as follows;

2x(x + 6) - 7x² + (13x - 3)

= 2x² + 12x - 7x² + 13x - 3

collect similar terms together

= (2x² - 7x²) + (12x + 13x) - 3

= -5x² + 25x - 3

Thus, the simplest form of the given expression can be written as -5x² + 25x - 3.

Learn more about simplification of algebras here: brainly.com/question/432678

7 0

2 years ago

NEED ANSWERS CORRECT ONES NEED NOW WILL MARK BRAINLIEST...

nadya68 [22]

(a) There are 1/4 cups of flour per serving

Work: 1.5/6=1/4

(b) There are aprox. .18 cups of sugar per serving.

Work: 9/12+4/12=13/12 n then divide 13/12 by 6

(c) You need 2 1/4 cups of flour to make 9 servings

Work: 1.5/2=.75 1.5+.75=2.25=2 1/4 cups

(d) Someone would need to know the amount of sugar per serving to make the recipe accurate.

Question 2

(a) You're account is at $10 dollars

Work: $5x5 (days)=$25. add 25 to -15 and you have $10 dollars in you're account.

(b) 5 days.

Work: 10/2=5 10-10=$0

6 0

2 years ago

Help please show your work answer 3 questions please Will Mark as a,brainless

liubo4ka [24]

Answer:

Step-by-step explanation:

7. C

30.D

34.A

8 0

3 years ago

Integrate sin^-1(x) dx please explain how to do it aswell ...?

Lynna [10]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2264253

_______________

Evaluate the indefinite integral:

$\mathsf{\displaystyle\int\!sin^{-1}(x)\,dx\qquad\quad\checkmark}$

Trigonometric substitution:

$\mathsf{\theta=sin^{-1}(x)\qquad\qquad\dfrac{\pi}{2}\le \theta\le \dfrac{\pi}{2}}$

then,

$\begin{array}{lcl} \mathsf{x=sin\,\theta}&\quad\Rightarrow\quad&\mathsf{dx=cos\,\theta\,d\theta\qquad\checkmark}\\\\\\ &&\mathsf{x^2=sin^2\,\theta}\\\\ &&\mathsf{x^2=1-cos^2\,\theta}\\\\ &&\mathsf{cos^2\,\theta=1-x^2}\\\\ &&\mathsf{cos\,\theta=\sqrt{1-x^2}\qquad\checkmark}\\\\\\ &&\textsf{because }\mathsf{cos\,\theta}\textsf{ is positive for }\mathsf{\theta\in \left[\dfrac{\pi}{2},\,\dfrac{\pi}{2}\right].} \end{array}$

So the integral $\mathsf{(ii)}$ becomes

$\mathsf{=\displaystyle\int\! \theta\,cos\,\theta\,d\theta\qquad\quad(ii)}$

Integrate $\mathsf{(ii)}$ by parts:

$\begin{array}{lcl} \mathsf{u=\theta}&\quad\Rightarrow\quad&\mathsf{du=d\theta}\\\\ \mathsf{dv=cos\,\theta\,d\theta}&\quad\Leftarrow\quad&\mathsf{v=sin\,\theta} \end{array}\\\\\\\\ \mathsf{\displaystyle\int\!u\,dv=u\cdot v-\int\!v\,du}\\\\\\ \mathsf{\displaystyle\int\!\theta\,cos\,\theta\,d\theta=\theta\, sin\,\theta-\int\!sin\,\theta\,d\theta}\\\\\\ \mathsf{\displaystyle\int\!\theta\,cos\,\theta\,d\theta=\theta\, sin\,\theta-(-cos\,\theta)+C}$

$\mathsf{\displaystyle\int\!\theta\,cos\,\theta\,d\theta=\theta\, sin\,\theta+cos\,\theta+C}$

Substitute back for the variable x, and you get

$\mathsf{\displaystyle\int\!sin^{-1}(x)\,dx=sin^{-1}(x)\cdot x+\sqrt{1-x^2}+C}\\\\\\\\ \therefore~~\mathsf{\displaystyle\int\!sin^{-1}(x)\,dx=x\cdot\,sin^{-1}(x)+\sqrt{1-x^2}+C\qquad\quad\checkmark}$

I hope this helps. =)

Tags: integral inverse sine function angle arcsin sine sin trigonometric trig substitution differential integral calculus

6 0

3 years ago