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Answer:
Work done in stretching the spring = 7.56 lb-ft.
Step-by-step explanation:
Normal length of the spring = 8 in or ft
= ft
If the spring has been stretched to 11 inch then the stretched length of the spring is = 11 in
= ft
Force applied to stretch the spring = 12 lb
By Hook's law,
F = kx [where k is the spring constant and x = length by which the spring is stretched]
12 = k()
k = 18
Work done (W) to stretch the spring by ft will be
W =
=
=
= 9()²
= 7.56 lb-ft
Answer:
See explanations for step by step procedure to answer
Step-by-step explanation:
Given that;
.f (x comma y )equals 8 x squared y minus 3 Confirm that the function f meets the conditions of the Second Derivative Test by finding f Subscript x Baseline (0 comma 0 ), f Subscript y Baseline (0 comma 0 ), and the second partial derivatives of f.
See attached documents for clearity, further explanations and answer
